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What is the purpose of this op amp configuration shown?

How does an op-amp become stable in this circuit?Would this JFET+op-amp circuit work?What's the purpose of this voltage noise test circuit?What is this RC local feedback configuration?inverting op-amp configuration using lm324n icOp Amp - Positive vs Negative feedback from the component levelOp-Amp for the 50MHz unity gain voltageWant to know more about this op-amp configurationSolving for V+ using VoutWhat is the purpose of the op-amp feedback circuit?

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1

$begingroup$

I've been researching common amplifier configurations, but the only ones with positive feedback that I have discovered is a negative resistance simulator, however that has negative feedback too.

operational-amplifier

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asked 1 hour ago

elecNoobelecNoob

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• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I think the point is for you to work out what it does for yourself.
  $endgroup$
  – Finbarr
  1 hour ago
  

  
  
  
  

add a comment | 

1

$begingroup$

I've been researching common amplifier configurations, but the only ones with positive feedback that I have discovered is a negative resistance simulator, however that has negative feedback too.

operational-amplifier

share|improve this question

asked 1 hour ago

elecNoobelecNoob

61

New contributor

elecNoob is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I think the point is for you to work out what it does for yourself.
  $endgroup$
  – Finbarr
  1 hour ago
  

  
  
  
  

add a comment | 

$begingroup$

I've been researching common amplifier configurations, but the only ones with positive feedback that I have discovered is a negative resistance simulator, however that has negative feedback too.

operational-amplifier

share|improve this question

asked 1 hour ago

elecNoobelecNoob

61

New contributor

elecNoob is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

share|improve this question

asked 1 hour ago

elecNoobelecNoob

61

New contributor

elecNoob is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 1 hour ago

elecNoobelecNoob

61

New contributor

elecNoob is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 1 hour ago

elecNoobelecNoob

61

New contributor

elecNoob is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 1 hour ago

elecNoobelecNoob

61

1 Answer
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$begingroup$

It's a comparator basically. It is a Schmitt trigger. It has a variable reference value, i.e. controlled using the R2 and R1 resistances. At the non-inverting input (using voltage divider arrangement), $$V_+ = fracR_1R_1 + R_2 * V_o$$ and at inverting input, $$ V_- = Vi $$ at the inverting terminal.

Now, output can be either $ +V_s $ or $ -V_s $ depending on whether non-inverting terminal voltage is higher or not respectively. So, the output is $beta V_s$ or $-beta V_s $ where $ beta = fracR_1R_1 + R_2 $.

If first output is in positive saturation and then $V_i$ goes above $beta V_s$, then output changes to $-V_s$. Similarly, when $V_i$ goes below $-beta V_s$, then output changes to $ +V_s$.

You can find a lot of websites that explain this circuit. Just search for Schmitt trigger.

share|improve this answer

edited 1 hour ago

answered 1 hour ago

akshayk07akshayk07

252116

$endgroup$

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2

$begingroup$

It's a comparator basically. It is a Schmitt trigger. It has a variable reference value, i.e. controlled using the R2 and R1 resistances. At the non-inverting input (using voltage divider arrangement), $$V_+ = fracR_1R_1 + R_2 * V_o$$ and at inverting input, $$ V_- = Vi $$ at the inverting terminal.

Now, output can be either $ +V_s $ or $ -V_s $ depending on whether non-inverting terminal voltage is higher or not respectively. So, the output is $beta V_s$ or $-beta V_s $ where $ beta = fracR_1R_1 + R_2 $.

If first output is in positive saturation and then $V_i$ goes above $beta V_s$, then output changes to $-V_s$. Similarly, when $V_i$ goes below $-beta V_s$, then output changes to $ +V_s$.

You can find a lot of websites that explain this circuit. Just search for Schmitt trigger.

share|improve this answer

edited 1 hour ago

answered 1 hour ago

akshayk07akshayk07

252116

$endgroup$

add a comment | 

2

$begingroup$

It's a comparator basically. It is a Schmitt trigger. It has a variable reference value, i.e. controlled using the R2 and R1 resistances. At the non-inverting input (using voltage divider arrangement), $$V_+ = fracR_1R_1 + R_2 * V_o$$ and at inverting input, $$ V_- = Vi $$ at the inverting terminal.

Now, output can be either $ +V_s $ or $ -V_s $ depending on whether non-inverting terminal voltage is higher or not respectively. So, the output is $beta V_s$ or $-beta V_s $ where $ beta = fracR_1R_1 + R_2 $.

If first output is in positive saturation and then $V_i$ goes above $beta V_s$, then output changes to $-V_s$. Similarly, when $V_i$ goes below $-beta V_s$, then output changes to $ +V_s$.

You can find a lot of websites that explain this circuit. Just search for Schmitt trigger.

share|improve this answer

edited 1 hour ago

answered 1 hour ago

akshayk07akshayk07

252116

$endgroup$

add a comment | 

$begingroup$

It's a comparator basically. It is a Schmitt trigger. It has a variable reference value, i.e. controlled using the R2 and R1 resistances. At the non-inverting input (using voltage divider arrangement), $$V_+ = fracR_1R_1 + R_2 * V_o$$ and at inverting input, $$ V_- = Vi $$ at the inverting terminal.

Now, output can be either $ +V_s $ or $ -V_s $ depending on whether non-inverting terminal voltage is higher or not respectively. So, the output is $beta V_s$ or $-beta V_s $ where $ beta = fracR_1R_1 + R_2 $.

If first output is in positive saturation and then $V_i$ goes above $beta V_s$, then output changes to $-V_s$. Similarly, when $V_i$ goes below $-beta V_s$, then output changes to $ +V_s$.

You can find a lot of websites that explain this circuit. Just search for Schmitt trigger.

share|improve this answer

edited 1 hour ago

answered 1 hour ago

akshayk07akshayk07

252116

$endgroup$

share|improve this answer

edited 1 hour ago

answered 1 hour ago

akshayk07akshayk07

252116

answered 1 hour ago

akshayk07akshayk07

252116

answered 1 hour ago

akshayk07akshayk07

252116