Does higher Oxidation/ reduction potential translate to higher energy storage in battery? The Next CEO of Stack OverflowCan we create a galvanic cell with only half a cell connected to the ground?How can Nernst equation apply in this redox reaction?What are some factors that influence the voltage of voltaic/galvanic cells and why?ElectrochemistryWhat factors could lower the voltage of a galvanic cellElectrode Potential and Effect of Salt Bridge Ions on its ValueWhy does a complete discharge destroy a Li-Ion-Battery?Is flow battery cycle life really as high as the literature claims?water in redox reactionsRelationship between Yield and Applied Potentials
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Does higher Oxidation/ reduction potential translate to higher energy storage in battery?
The Next CEO of Stack OverflowCan we create a galvanic cell with only half a cell connected to the ground?How can Nernst equation apply in this redox reaction?What are some factors that influence the voltage of voltaic/galvanic cells and why?ElectrochemistryWhat factors could lower the voltage of a galvanic cellElectrode Potential and Effect of Salt Bridge Ions on its ValueWhy does a complete discharge destroy a Li-Ion-Battery?Is flow battery cycle life really as high as the literature claims?water in redox reactionsRelationship between Yield and Applied Potentials
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Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
New contributor
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add a comment |
$begingroup$
Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
New contributor
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1
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago
add a comment |
$begingroup$
Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
New contributor
$endgroup$
Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
electrochemistry
New contributor
New contributor
New contributor
asked 8 hours ago
Karthick SKarthick S
111
111
New contributor
New contributor
1
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago
add a comment |
1
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago
1
1
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
$endgroup$
add a comment |
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$begingroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
$endgroup$
add a comment |
$begingroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
$endgroup$
add a comment |
$begingroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
$endgroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
edited 56 mins ago
answered 6 hours ago
DrMoishe PippikDrMoishe Pippik
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Karthick S is a new contributor. Be nice, and check out our Code of Conduct.
Karthick S is a new contributor. Be nice, and check out our Code of Conduct.
Karthick S is a new contributor. Be nice, and check out our Code of Conduct.
Karthick S is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
7 hours ago