New Order #6: Easter Egg Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) The PPCG Site design is on its way - help us make it awesome! Sandbox for Proposed ChallengesNew order #4: WorldNew Order #2: Turn My WayNew Order #1: How does this feel?New Order #5: where Fibonacci and Beatty meet at WythoffNew Order #3: 5 8 6Challenge UlamspiralFind the angle between two pointsTriangular Ulam spiralAsterisk spiralReturn Spiral Indexes!New Order #1: How does this feel?New Order #2: Turn My WayNew Order #3: 5 8 6New order #4: WorldNew Order #5: where Fibonacci and Beatty meet at Wythoff

Is there public access to the Meteor Crater in Arizona?

Resize vertical bars (absolute-value symbols)

Asymptotics question

Printing attributes of selection in ArcPy?

How many morphisms from 1 to 1+1 can there be?

I can't produce songs

What initially awakened the Balrog?

How many time has Arya actually used Needle?

Should a wizard buy fine inks every time he want to copy spells into his spellbook?

Why not send Voyager 3 and 4 following up the paths taken by Voyager 1 and 2 to re-transmit signals of later as they fly away from Earth?

Why are vacuum tubes still used in amateur radios?

How to write capital alpha?

Do I really need to have a message in a novel to appeal to readers?

Is there more forest in the Northern Hemisphere now than 100 years ago?

BITCOIN: on a chart what does it mean for the USD price to be higher then marketcap?

Understanding p-Values using an example

What does 丫 mean? 丫是什么意思?

Monty Hall Problem-Probability Paradox

Project Euler #1 in C++

Why datecode is SO IMPORTANT to chip manufacturers?

"klopfte jemand" or "jemand klopfte"?

Can an iPhone 7 be made to function as a NFC Tag?

The Nth Gryphon Number

What is the chair depicted in Cesare Maccari's 1889 painting "Cicerone denuncia Catilina"?



New Order #6: Easter Egg



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
The PPCG Site design is on its way - help us make it awesome!
Sandbox for Proposed ChallengesNew order #4: WorldNew Order #2: Turn My WayNew Order #1: How does this feel?New Order #5: where Fibonacci and Beatty meet at WythoffNew Order #3: 5 8 6Challenge UlamspiralFind the angle between two pointsTriangular Ulam spiralAsterisk spiralReturn Spiral Indexes!New Order #1: How does this feel?New Order #2: Turn My WayNew Order #3: 5 8 6New order #4: WorldNew Order #5: where Fibonacci and Beatty meet at Wythoff










2












$begingroup$


Introduction (may be ignored)



Putting all positive integers in its regular order (1, 2, 3, ...) is a bit boring, isn't it? So here is a series of challenges around permutations (reshuffelings) of all positive integers. This is the sixth challenge in this series (links to the first, second, third, fourth and fifth challenge).



This challenge has a mild Easter theme (because it's Easter). I took my inspiration from this highly decorated (and in my personal opinion rather ugly) goose egg.



Decorated goose egg



It reminded me of the Ulam spiral, where all positive integers are placed in a counter-clockwise spiral. This spiral has some interesting features related to prime numbers, but that's not relevant for this challenge.



Ulam spiral



We get to this challenge's permutation of positive integers if we take the numbers in the Ulam spiral and trace all integers in a clockwise turning spiral, starting at 1. This way, we get:



1, 6, 5, 4, 3, 2, 9, 8, 7, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 25, 24, 23, etc.


If you would draw both of the spirals, you'd get some sort of an infinite mesh of (egg shell) spirals (note the New Order reference there).



This sequence is present in the OEIS under number A090861. Since this is a "pure sequence" challenge, the task is to output $a(n)$ for a given $n$ as input, where $a(n)$ is A090861.



Task



Given an integer input $n$, output $a(n)$ in integer format, where $a(n)$ is A090861.



Note: 1-based indexing is assumed here; you may use 0-based indexing, so $a(0) = 1; a(1) = 6$, etc. Please mention this in your answer if you choose to use this.



Test cases



Input | Output
---------------
1 | 1
5 | 3
20 | 10
50 | 72
78 | 76
123 | 155
1234 | 1324
3000 | 2996
9999 | 9903
29890 | 29796


Rules



  • Input and output are integers.

  • Your program should at least support input in the range of 1 up to 32767).

  • Invalid input (0, floats, strings, negative values, etc.) may lead to unpredicted output, errors or (un)defined behaviour.

  • Default I/O rules apply.


  • Default loopholes are forbidden.

  • This is code-golf, so the shortest answers in bytes wins









share|improve this question









$endgroup$
















    2












    $begingroup$


    Introduction (may be ignored)



    Putting all positive integers in its regular order (1, 2, 3, ...) is a bit boring, isn't it? So here is a series of challenges around permutations (reshuffelings) of all positive integers. This is the sixth challenge in this series (links to the first, second, third, fourth and fifth challenge).



    This challenge has a mild Easter theme (because it's Easter). I took my inspiration from this highly decorated (and in my personal opinion rather ugly) goose egg.



    Decorated goose egg



    It reminded me of the Ulam spiral, where all positive integers are placed in a counter-clockwise spiral. This spiral has some interesting features related to prime numbers, but that's not relevant for this challenge.



    Ulam spiral



    We get to this challenge's permutation of positive integers if we take the numbers in the Ulam spiral and trace all integers in a clockwise turning spiral, starting at 1. This way, we get:



    1, 6, 5, 4, 3, 2, 9, 8, 7, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 25, 24, 23, etc.


    If you would draw both of the spirals, you'd get some sort of an infinite mesh of (egg shell) spirals (note the New Order reference there).



    This sequence is present in the OEIS under number A090861. Since this is a "pure sequence" challenge, the task is to output $a(n)$ for a given $n$ as input, where $a(n)$ is A090861.



    Task



    Given an integer input $n$, output $a(n)$ in integer format, where $a(n)$ is A090861.



    Note: 1-based indexing is assumed here; you may use 0-based indexing, so $a(0) = 1; a(1) = 6$, etc. Please mention this in your answer if you choose to use this.



    Test cases



    Input | Output
    ---------------
    1 | 1
    5 | 3
    20 | 10
    50 | 72
    78 | 76
    123 | 155
    1234 | 1324
    3000 | 2996
    9999 | 9903
    29890 | 29796


    Rules



    • Input and output are integers.

    • Your program should at least support input in the range of 1 up to 32767).

    • Invalid input (0, floats, strings, negative values, etc.) may lead to unpredicted output, errors or (un)defined behaviour.

    • Default I/O rules apply.


    • Default loopholes are forbidden.

    • This is code-golf, so the shortest answers in bytes wins









    share|improve this question









    $endgroup$














      2












      2








      2





      $begingroup$


      Introduction (may be ignored)



      Putting all positive integers in its regular order (1, 2, 3, ...) is a bit boring, isn't it? So here is a series of challenges around permutations (reshuffelings) of all positive integers. This is the sixth challenge in this series (links to the first, second, third, fourth and fifth challenge).



      This challenge has a mild Easter theme (because it's Easter). I took my inspiration from this highly decorated (and in my personal opinion rather ugly) goose egg.



      Decorated goose egg



      It reminded me of the Ulam spiral, where all positive integers are placed in a counter-clockwise spiral. This spiral has some interesting features related to prime numbers, but that's not relevant for this challenge.



      Ulam spiral



      We get to this challenge's permutation of positive integers if we take the numbers in the Ulam spiral and trace all integers in a clockwise turning spiral, starting at 1. This way, we get:



      1, 6, 5, 4, 3, 2, 9, 8, 7, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 25, 24, 23, etc.


      If you would draw both of the spirals, you'd get some sort of an infinite mesh of (egg shell) spirals (note the New Order reference there).



      This sequence is present in the OEIS under number A090861. Since this is a "pure sequence" challenge, the task is to output $a(n)$ for a given $n$ as input, where $a(n)$ is A090861.



      Task



      Given an integer input $n$, output $a(n)$ in integer format, where $a(n)$ is A090861.



      Note: 1-based indexing is assumed here; you may use 0-based indexing, so $a(0) = 1; a(1) = 6$, etc. Please mention this in your answer if you choose to use this.



      Test cases



      Input | Output
      ---------------
      1 | 1
      5 | 3
      20 | 10
      50 | 72
      78 | 76
      123 | 155
      1234 | 1324
      3000 | 2996
      9999 | 9903
      29890 | 29796


      Rules



      • Input and output are integers.

      • Your program should at least support input in the range of 1 up to 32767).

      • Invalid input (0, floats, strings, negative values, etc.) may lead to unpredicted output, errors or (un)defined behaviour.

      • Default I/O rules apply.


      • Default loopholes are forbidden.

      • This is code-golf, so the shortest answers in bytes wins









      share|improve this question









      $endgroup$




      Introduction (may be ignored)



      Putting all positive integers in its regular order (1, 2, 3, ...) is a bit boring, isn't it? So here is a series of challenges around permutations (reshuffelings) of all positive integers. This is the sixth challenge in this series (links to the first, second, third, fourth and fifth challenge).



      This challenge has a mild Easter theme (because it's Easter). I took my inspiration from this highly decorated (and in my personal opinion rather ugly) goose egg.



      Decorated goose egg



      It reminded me of the Ulam spiral, where all positive integers are placed in a counter-clockwise spiral. This spiral has some interesting features related to prime numbers, but that's not relevant for this challenge.



      Ulam spiral



      We get to this challenge's permutation of positive integers if we take the numbers in the Ulam spiral and trace all integers in a clockwise turning spiral, starting at 1. This way, we get:



      1, 6, 5, 4, 3, 2, 9, 8, 7, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 25, 24, 23, etc.


      If you would draw both of the spirals, you'd get some sort of an infinite mesh of (egg shell) spirals (note the New Order reference there).



      This sequence is present in the OEIS under number A090861. Since this is a "pure sequence" challenge, the task is to output $a(n)$ for a given $n$ as input, where $a(n)$ is A090861.



      Task



      Given an integer input $n$, output $a(n)$ in integer format, where $a(n)$ is A090861.



      Note: 1-based indexing is assumed here; you may use 0-based indexing, so $a(0) = 1; a(1) = 6$, etc. Please mention this in your answer if you choose to use this.



      Test cases



      Input | Output
      ---------------
      1 | 1
      5 | 3
      20 | 10
      50 | 72
      78 | 76
      123 | 155
      1234 | 1324
      3000 | 2996
      9999 | 9903
      29890 | 29796


      Rules



      • Input and output are integers.

      • Your program should at least support input in the range of 1 up to 32767).

      • Invalid input (0, floats, strings, negative values, etc.) may lead to unpredicted output, errors or (un)defined behaviour.

      • Default I/O rules apply.


      • Default loopholes are forbidden.

      • This is code-golf, so the shortest answers in bytes wins






      code-golf sequence






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 1 hour ago









      agtoeveragtoever

      1,416425




      1,416425




















          5 Answers
          5






          active

          oldest

          votes


















          1












          $begingroup$


          Wolfram Language (Mathematica), 60 bytes



          8(s=⌊(⌊Sqrt[#-1]⌋+1)/2⌋)^2-#+2+If[#<=4s^2+2s,-2,6]s&


          Try it online!






          share|improve this answer









          $endgroup$




















            1












            $begingroup$


            C# (Visual C# Interactive Compiler), 67 bytes





            n=>8*(x=(int)Math.Sqrt(--n)+1>>1)*x+(n<4*x*x+2*x?-2:6)*x+1-n;int x;


            Try it online!






            share|improve this answer











            $endgroup$




















              1












              $begingroup$


              MATL, 12 bytes



              Eq1YL!tPwG=)


              Try it online!



              Very memory-inefficient. Prepending X^k makes it more efficient.






              share|improve this answer









              $endgroup$




















                1












                $begingroup$


                Jelly,  16  14 bytes



                2,6×Ɱ’ẎÄRUẎQị@


                A monadic Link accepting an integer, n, which yields an integer, a(n).



                Try it online! (very inefficient)






                share|improve this answer











                $endgroup$




















                  1












                  $begingroup$

                  JavaScript (ES7),  46 45  41 bytes



                  0-indexed.





                  n=>((x=n**.5+1&~1)*2-(n<x*x+x)*4+3)*x+1-n


                  Try it online!






                  share|improve this answer











                  $endgroup$













                    Your Answer






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                    5 Answers
                    5






                    active

                    oldest

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                    5 Answers
                    5






                    active

                    oldest

                    votes









                    active

                    oldest

                    votes






                    active

                    oldest

                    votes









                    1












                    $begingroup$


                    Wolfram Language (Mathematica), 60 bytes



                    8(s=⌊(⌊Sqrt[#-1]⌋+1)/2⌋)^2-#+2+If[#<=4s^2+2s,-2,6]s&


                    Try it online!






                    share|improve this answer









                    $endgroup$

















                      1












                      $begingroup$


                      Wolfram Language (Mathematica), 60 bytes



                      8(s=⌊(⌊Sqrt[#-1]⌋+1)/2⌋)^2-#+2+If[#<=4s^2+2s,-2,6]s&


                      Try it online!






                      share|improve this answer









                      $endgroup$















                        1












                        1








                        1





                        $begingroup$


                        Wolfram Language (Mathematica), 60 bytes



                        8(s=⌊(⌊Sqrt[#-1]⌋+1)/2⌋)^2-#+2+If[#<=4s^2+2s,-2,6]s&


                        Try it online!






                        share|improve this answer









                        $endgroup$




                        Wolfram Language (Mathematica), 60 bytes



                        8(s=⌊(⌊Sqrt[#-1]⌋+1)/2⌋)^2-#+2+If[#<=4s^2+2s,-2,6]s&


                        Try it online!







                        share|improve this answer












                        share|improve this answer



                        share|improve this answer










                        answered 56 mins ago









                        J42161217J42161217

                        14.3k21354




                        14.3k21354





















                            1












                            $begingroup$


                            C# (Visual C# Interactive Compiler), 67 bytes





                            n=>8*(x=(int)Math.Sqrt(--n)+1>>1)*x+(n<4*x*x+2*x?-2:6)*x+1-n;int x;


                            Try it online!






                            share|improve this answer











                            $endgroup$

















                              1












                              $begingroup$


                              C# (Visual C# Interactive Compiler), 67 bytes





                              n=>8*(x=(int)Math.Sqrt(--n)+1>>1)*x+(n<4*x*x+2*x?-2:6)*x+1-n;int x;


                              Try it online!






                              share|improve this answer











                              $endgroup$















                                1












                                1








                                1





                                $begingroup$


                                C# (Visual C# Interactive Compiler), 67 bytes





                                n=>8*(x=(int)Math.Sqrt(--n)+1>>1)*x+(n<4*x*x+2*x?-2:6)*x+1-n;int x;


                                Try it online!






                                share|improve this answer











                                $endgroup$




                                C# (Visual C# Interactive Compiler), 67 bytes





                                n=>8*(x=(int)Math.Sqrt(--n)+1>>1)*x+(n<4*x*x+2*x?-2:6)*x+1-n;int x;


                                Try it online!







                                share|improve this answer














                                share|improve this answer



                                share|improve this answer








                                edited 27 mins ago

























                                answered 40 mins ago









                                Embodiment of IgnoranceEmbodiment of Ignorance

                                3,044127




                                3,044127





















                                    1












                                    $begingroup$


                                    MATL, 12 bytes



                                    Eq1YL!tPwG=)


                                    Try it online!



                                    Very memory-inefficient. Prepending X^k makes it more efficient.






                                    share|improve this answer









                                    $endgroup$

















                                      1












                                      $begingroup$


                                      MATL, 12 bytes



                                      Eq1YL!tPwG=)


                                      Try it online!



                                      Very memory-inefficient. Prepending X^k makes it more efficient.






                                      share|improve this answer









                                      $endgroup$















                                        1












                                        1








                                        1





                                        $begingroup$


                                        MATL, 12 bytes



                                        Eq1YL!tPwG=)


                                        Try it online!



                                        Very memory-inefficient. Prepending X^k makes it more efficient.






                                        share|improve this answer









                                        $endgroup$




                                        MATL, 12 bytes



                                        Eq1YL!tPwG=)


                                        Try it online!



                                        Very memory-inefficient. Prepending X^k makes it more efficient.







                                        share|improve this answer












                                        share|improve this answer



                                        share|improve this answer










                                        answered 18 mins ago









                                        Luis MendoLuis Mendo

                                        75.5k889293




                                        75.5k889293





















                                            1












                                            $begingroup$


                                            Jelly,  16  14 bytes



                                            2,6×Ɱ’ẎÄRUẎQị@


                                            A monadic Link accepting an integer, n, which yields an integer, a(n).



                                            Try it online! (very inefficient)






                                            share|improve this answer











                                            $endgroup$

















                                              1












                                              $begingroup$


                                              Jelly,  16  14 bytes



                                              2,6×Ɱ’ẎÄRUẎQị@


                                              A monadic Link accepting an integer, n, which yields an integer, a(n).



                                              Try it online! (very inefficient)






                                              share|improve this answer











                                              $endgroup$















                                                1












                                                1








                                                1





                                                $begingroup$


                                                Jelly,  16  14 bytes



                                                2,6×Ɱ’ẎÄRUẎQị@


                                                A monadic Link accepting an integer, n, which yields an integer, a(n).



                                                Try it online! (very inefficient)






                                                share|improve this answer











                                                $endgroup$




                                                Jelly,  16  14 bytes



                                                2,6×Ɱ’ẎÄRUẎQị@


                                                A monadic Link accepting an integer, n, which yields an integer, a(n).



                                                Try it online! (very inefficient)







                                                share|improve this answer














                                                share|improve this answer



                                                share|improve this answer








                                                edited 11 mins ago

























                                                answered 17 mins ago









                                                Jonathan AllanJonathan Allan

                                                54.7k537175




                                                54.7k537175





















                                                    1












                                                    $begingroup$

                                                    JavaScript (ES7),  46 45  41 bytes



                                                    0-indexed.





                                                    n=>((x=n**.5+1&~1)*2-(n<x*x+x)*4+3)*x+1-n


                                                    Try it online!






                                                    share|improve this answer











                                                    $endgroup$

















                                                      1












                                                      $begingroup$

                                                      JavaScript (ES7),  46 45  41 bytes



                                                      0-indexed.





                                                      n=>((x=n**.5+1&~1)*2-(n<x*x+x)*4+3)*x+1-n


                                                      Try it online!






                                                      share|improve this answer











                                                      $endgroup$















                                                        1












                                                        1








                                                        1





                                                        $begingroup$

                                                        JavaScript (ES7),  46 45  41 bytes



                                                        0-indexed.





                                                        n=>((x=n**.5+1&~1)*2-(n<x*x+x)*4+3)*x+1-n


                                                        Try it online!






                                                        share|improve this answer











                                                        $endgroup$



                                                        JavaScript (ES7),  46 45  41 bytes



                                                        0-indexed.





                                                        n=>((x=n**.5+1&~1)*2-(n<x*x+x)*4+3)*x+1-n


                                                        Try it online!







                                                        share|improve this answer














                                                        share|improve this answer



                                                        share|improve this answer








                                                        edited 4 mins ago

























                                                        answered 29 mins ago









                                                        ArnauldArnauld

                                                        81.7k798337




                                                        81.7k798337



























                                                            draft saved

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                                                            If this is an answer to a challenge…



                                                            • …Be sure to follow the challenge specification. However, please refrain from exploiting obvious loopholes. Answers abusing any of the standard loopholes are considered invalid. If you think a specification is unclear or underspecified, comment on the question instead.


                                                            • …Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one.
                                                              Explanations of your answer make it more interesting to read and are very much encouraged.


                                                            • …Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.


                                                            More generally…



                                                            • …Please make sure to answer the question and provide sufficient detail.


                                                            • …Avoid asking for help, clarification or responding to other answers (use comments instead).




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                                                            Тонконіг бульбистий Зміст Опис | Поширення | Екологія | Господарське значення | Примітки | Див. також | Література | Джерела | Посилання | Навігаційне меню1114601320038-241116202404kew-435458Poa bulbosaЭлектронный каталог сосудистых растений Азиатской России [Електронний каталог судинних рослин Азіатської Росії]Малышев Л. Л. Дикие родичи культурных растений. Poa bulbosa L. - Мятлик луковичный. [Малишев Л. Л. Дикі родичи культурних рослин. Poa bulbosa L. - Тонконіг бульбистий.]Мятлик (POA) Сем. Злаки (Мятликовые) [Тонконіг (POA) Род. Злаки (Тонконогові)]Poa bulbosa Linnaeus, Sp. Pl. 1: 70. 1753. 鳞茎早熟禾 lin jing zao shu he (Description from Flora of China) [Poa bulbosa Linnaeus, Sp. Pl. 1: 70. 1753. 鳞茎早熟禾 lin jing zao shu he (Опис від Флора Китаю)]Poa bulbosa L. – lipnice cibulkatá / lipnica cibulkatáPoa bulbosa в базі даних Poa bulbosa на сайті Poa bulbosa в базі даних «Global Biodiversity Information Facility» (GBIF)Poa bulbosa в базі даних «Euro + Med PlantBase» — інформаційному ресурсі для Євро-середземноморського розмаїття рослинPoa bulbosa L. на сайті «Плантариум»

                                                            Вунгтау (аеропорт) Загальні відомості | Див. також | Посилання | Навігаційне меню10°22′00″ пн. ш. 107°05′00″ сх. д. / 10.36667° пн. ш. 107.08333° сх. д. / 10.36667; 107.0833310°22′00″ пн. ш. 107°05′00″ сх. д. / 10.36667° пн. ш. 107.08333° сх. д. / 10.36667; 107.083337731608Vinh AirportVinh airport facelift improves serviceвиправивши або дописавши їївиправивши або дописавши їїр