GraphicsGrid with a Label for each Column and RowPutting a vertical line in each Histogram using GraphicsGridComposite graphics with Row, Column, data aggregation and layout controlControl objects Sizing and placement in Graphicsgrid Vs Grid:Label each panel of GridCombining ArrayPlot and PlotGraphicsGrid Format Problem with SpanFromAboveConstructing a grid from a matrixHow to solve for the intersection points of two ellipses?How to use GraphicsGrid with ListPlots that have a PlotLegend?Rotated Row and Normal Column Headings for a GridPutting a vertical line in each Histogram using GraphicsGrid
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GraphicsGrid with a Label for each Column and Row
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GraphicsGrid with a Label for each Column and Row
Putting a vertical line in each Histogram using GraphicsGridComposite graphics with Row, Column, data aggregation and layout controlControl objects Sizing and placement in Graphicsgrid Vs Grid:Label each panel of GridCombining ArrayPlot and PlotGraphicsGrid Format Problem with SpanFromAboveConstructing a grid from a matrixHow to solve for the intersection points of two ellipses?How to use GraphicsGrid with ListPlots that have a PlotLegend?Rotated Row and Normal Column Headings for a GridPutting a vertical line in each Histogram using GraphicsGrid
$begingroup$
Is it possible to use GraphicsGrid and do something like this?
$beginarraycccc
textX & Label1 & Label2& Label3\
Label4 & Plot1 & Plot2&Plot3\
Label5 & Plot4 & Plot5&Plot6\
Label6 & Plot7 & Plot8&Plot9\
endarray $
graphics visualization
asked 4 hours ago
An old man in the sea.An old man in the sea.
1,084919
$endgroup$
add a comment |
$begingroup$
Is it possible to use GraphicsGrid and do something like this?
$beginarraycccc
textX & Label1 & Label2& Label3\
Label4 & Plot1 & Plot2&Plot3\
Label5 & Plot4 & Plot5&Plot6\
Label6 & Plot7 & Plot8&Plot9\
endarray $
graphics visualization
asked 4 hours ago
An old man in the sea.An old man in the sea.
1,084919
$endgroup$
add a comment |
$begingroup$
Is it possible to use GraphicsGrid and do something like this?
$beginarraycccc
textX & Label1 & Label2& Label3\
Label4 & Plot1 & Plot2&Plot3\
Label5 & Plot4 & Plot5&Plot6\
Label6 & Plot7 & Plot8&Plot9\
endarray $
graphics visualization
asked 4 hours ago
An old man in the sea.An old man in the sea.
1,084919
$endgroup$
Is it possible to use GraphicsGrid and do something like this?
$beginarraycccc
textX & Label1 & Label2& Label3\
Label4 & Plot1 & Plot2&Plot3\
Label5 & Plot4 & Plot5&Plot6\
Label6 & Plot7 & Plot8&Plot9\
endarray $
graphics visualization
graphics visualization
asked 4 hours ago
An old man in the sea.An old man in the sea.
1,084919
asked 4 hours ago
An old man in the sea.An old man in the sea.
1,084919
asked 4 hours ago
An old man in the sea.An old man in the sea.
1,084919
asked 4 hours ago
An old man in the sea.An old man in the sea.
1,084919
asked 4 hours ago
An old man in the sea.An old man in the sea.
1,084919
1,084919
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:
Make a 3 x 3 array of graphics (this is adopted from a previous answer}
circles[n_] :=
Module[r, cntr, r := RandomReal[.25];
cntr := RandomReal[1, 2];
Graphics[
Table[EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r], n],
PlotRange -> 0, 1, 0, 1, PlotRangeClipping -> True,
Frame -> True]
lines[] :=
Module[lf, rt,
lf := With[x = RandomReal[.48], Red, Line[x, 0, x, 1]];
rt := With[x = RandomReal[.52, 1], Blue,
Line[x, 0, x, 1]];
Graphics[lf, rt, PlotRange -> 0, 1, 0, 1,
PlotRangeClipping -> True, Frame -> True]]
SeedRandom[4];
graphics =
Apply[Show,
Partition[Transpose[Table[circles[8], 9], Table[lines[], 9]],
3], 2];
Make the headers:
colHeaders, rowHeaders = Partition[Table[Style[Row["Label", i], "TBI"], i, 6], 3];
Make the grid with TableForm:
TableForm[graphics, TableHeadings -> rowHeaders, colHeaders]
answered 38 mins ago
m_goldbergm_goldberg
87.7k872198
$endgroup$
add a comment |
$begingroup$
Here is an option:
plots = Table[Table[Plot[Sin[i x + j], x, 1, 10], i, 3], j, 3];
xlabels = "", "Label 1", "Label 2", "Label 3";
ylabels = "Label 4", "Label 5", "Label 6";
GraphicsGrid[Join[xlabels, Transpose[Join[ylabels, Transpose[plots]]]]]
answered 3 hours ago
MelaGoMelaGo
4963
$endgroup$
add a comment |
$begingroup$
You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.
plotGrid = Table[Plot[Sin[x], x, 0, 2 Pi], 2, 2];
plotRowHeader =
Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], i, 2];
plotColumnHeader =
Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], i, 3,
4] // Prepend[Graphics[Style[Text["X"], 12]]];
graphicsGrid =
plotGrid // Prepend[plotRowHeader] // Transpose //
Prepend[plotColumnHeader];
GraphicsGrid[graphicsGrid]
answered 3 hours ago
Rohit NamjoshiRohit Namjoshi
1,4921213
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:
Make a 3 x 3 array of graphics (this is adopted from a previous answer}
circles[n_] :=
Module[r, cntr, r := RandomReal[.25];
cntr := RandomReal[1, 2];
Graphics[
Table[EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r], n],
PlotRange -> 0, 1, 0, 1, PlotRangeClipping -> True,
Frame -> True]
lines[] :=
Module[lf, rt,
lf := With[x = RandomReal[.48], Red, Line[x, 0, x, 1]];
rt := With[x = RandomReal[.52, 1], Blue,
Line[x, 0, x, 1]];
Graphics[lf, rt, PlotRange -> 0, 1, 0, 1,
PlotRangeClipping -> True, Frame -> True]]
SeedRandom[4];
graphics =
Apply[Show,
Partition[Transpose[Table[circles[8], 9], Table[lines[], 9]],
3], 2];
Make the headers:
colHeaders, rowHeaders = Partition[Table[Style[Row["Label", i], "TBI"], i, 6], 3];
Make the grid with TableForm:
TableForm[graphics, TableHeadings -> rowHeaders, colHeaders]
answered 38 mins ago
m_goldbergm_goldberg
87.7k872198
$endgroup$
add a comment |
$begingroup$
If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:
Make a 3 x 3 array of graphics (this is adopted from a previous answer}
circles[n_] :=
Module[r, cntr, r := RandomReal[.25];
cntr := RandomReal[1, 2];
Graphics[
Table[EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r], n],
PlotRange -> 0, 1, 0, 1, PlotRangeClipping -> True,
Frame -> True]
lines[] :=
Module[lf, rt,
lf := With[x = RandomReal[.48], Red, Line[x, 0, x, 1]];
rt := With[x = RandomReal[.52, 1], Blue,
Line[x, 0, x, 1]];
Graphics[lf, rt, PlotRange -> 0, 1, 0, 1,
PlotRangeClipping -> True, Frame -> True]]
SeedRandom[4];
graphics =
Apply[Show,
Partition[Transpose[Table[circles[8], 9], Table[lines[], 9]],
3], 2];
Make the headers:
colHeaders, rowHeaders = Partition[Table[Style[Row["Label", i], "TBI"], i, 6], 3];
Make the grid with TableForm:
TableForm[graphics, TableHeadings -> rowHeaders, colHeaders]
answered 38 mins ago
m_goldbergm_goldberg
87.7k872198
$endgroup$
add a comment |
$begingroup$
If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:
Make a 3 x 3 array of graphics (this is adopted from a previous answer}
circles[n_] :=
Module[r, cntr, r := RandomReal[.25];
cntr := RandomReal[1, 2];
Graphics[
Table[EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r], n],
PlotRange -> 0, 1, 0, 1, PlotRangeClipping -> True,
Frame -> True]
lines[] :=
Module[lf, rt,
lf := With[x = RandomReal[.48], Red, Line[x, 0, x, 1]];
rt := With[x = RandomReal[.52, 1], Blue,
Line[x, 0, x, 1]];
Graphics[lf, rt, PlotRange -> 0, 1, 0, 1,
PlotRangeClipping -> True, Frame -> True]]
SeedRandom[4];
graphics =
Apply[Show,
Partition[Transpose[Table[circles[8], 9], Table[lines[], 9]],
3], 2];
Make the headers:
colHeaders, rowHeaders = Partition[Table[Style[Row["Label", i], "TBI"], i, 6], 3];
Make the grid with TableForm:
TableForm[graphics, TableHeadings -> rowHeaders, colHeaders]
answered 38 mins ago
m_goldbergm_goldberg
87.7k872198
$endgroup$
If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:
Make a 3 x 3 array of graphics (this is adopted from a previous answer}
circles[n_] :=
Module[r, cntr, r := RandomReal[.25];
cntr := RandomReal[1, 2];
Graphics[
Table[EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r], n],
PlotRange -> 0, 1, 0, 1, PlotRangeClipping -> True,
Frame -> True]
lines[] :=
Module[lf, rt,
lf := With[x = RandomReal[.48], Red, Line[x, 0, x, 1]];
rt := With[x = RandomReal[.52, 1], Blue,
Line[x, 0, x, 1]];
Graphics[lf, rt, PlotRange -> 0, 1, 0, 1,
PlotRangeClipping -> True, Frame -> True]]
SeedRandom[4];
graphics =
Apply[Show,
Partition[Transpose[Table[circles[8], 9], Table[lines[], 9]],
3], 2];
Make the headers:
colHeaders, rowHeaders = Partition[Table[Style[Row["Label", i], "TBI"], i, 6], 3];
Make the grid with TableForm:
TableForm[graphics, TableHeadings -> rowHeaders, colHeaders]
answered 38 mins ago
m_goldbergm_goldberg
87.7k872198
answered 38 mins ago
m_goldbergm_goldberg
87.7k872198
answered 38 mins ago
m_goldbergm_goldberg
87.7k872198
answered 38 mins ago
m_goldbergm_goldberg
87.7k872198
87.7k872198
add a comment |
add a comment |
$begingroup$
Here is an option:
plots = Table[Table[Plot[Sin[i x + j], x, 1, 10], i, 3], j, 3];
xlabels = "", "Label 1", "Label 2", "Label 3";
ylabels = "Label 4", "Label 5", "Label 6";
GraphicsGrid[Join[xlabels, Transpose[Join[ylabels, Transpose[plots]]]]]
answered 3 hours ago
MelaGoMelaGo
4963
$endgroup$
add a comment |
$begingroup$
Here is an option:
plots = Table[Table[Plot[Sin[i x + j], x, 1, 10], i, 3], j, 3];
xlabels = "", "Label 1", "Label 2", "Label 3";
ylabels = "Label 4", "Label 5", "Label 6";
GraphicsGrid[Join[xlabels, Transpose[Join[ylabels, Transpose[plots]]]]]
answered 3 hours ago
MelaGoMelaGo
4963
$endgroup$
add a comment |
$begingroup$
Here is an option:
plots = Table[Table[Plot[Sin[i x + j], x, 1, 10], i, 3], j, 3];
xlabels = "", "Label 1", "Label 2", "Label 3";
ylabels = "Label 4", "Label 5", "Label 6";
GraphicsGrid[Join[xlabels, Transpose[Join[ylabels, Transpose[plots]]]]]
answered 3 hours ago
MelaGoMelaGo
4963
$endgroup$
Here is an option:
plots = Table[Table[Plot[Sin[i x + j], x, 1, 10], i, 3], j, 3];
xlabels = "", "Label 1", "Label 2", "Label 3";
ylabels = "Label 4", "Label 5", "Label 6";
GraphicsGrid[Join[xlabels, Transpose[Join[ylabels, Transpose[plots]]]]]
answered 3 hours ago
MelaGoMelaGo
4963
answered 3 hours ago
MelaGoMelaGo
4963
answered 3 hours ago
MelaGoMelaGo
4963
answered 3 hours ago
MelaGoMelaGo
4963
4963
add a comment |
add a comment |
$begingroup$
You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.
plotGrid = Table[Plot[Sin[x], x, 0, 2 Pi], 2, 2];
plotRowHeader =
Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], i, 2];
plotColumnHeader =
Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], i, 3,
4] // Prepend[Graphics[Style[Text["X"], 12]]];
graphicsGrid =
plotGrid // Prepend[plotRowHeader] // Transpose //
Prepend[plotColumnHeader];
GraphicsGrid[graphicsGrid]
answered 3 hours ago
Rohit NamjoshiRohit Namjoshi
1,4921213
$endgroup$
add a comment |
$begingroup$
You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.
plotGrid = Table[Plot[Sin[x], x, 0, 2 Pi], 2, 2];
plotRowHeader =
Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], i, 2];
plotColumnHeader =
Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], i, 3,
4] // Prepend[Graphics[Style[Text["X"], 12]]];
graphicsGrid =
plotGrid // Prepend[plotRowHeader] // Transpose //
Prepend[plotColumnHeader];
GraphicsGrid[graphicsGrid]
answered 3 hours ago
Rohit NamjoshiRohit Namjoshi
1,4921213
$endgroup$
add a comment |
$begingroup$
You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.
plotGrid = Table[Plot[Sin[x], x, 0, 2 Pi], 2, 2];
plotRowHeader =
Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], i, 2];
plotColumnHeader =
Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], i, 3,
4] // Prepend[Graphics[Style[Text["X"], 12]]];
graphicsGrid =
plotGrid // Prepend[plotRowHeader] // Transpose //
Prepend[plotColumnHeader];
GraphicsGrid[graphicsGrid]
answered 3 hours ago
Rohit NamjoshiRohit Namjoshi
1,4921213
$endgroup$
You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.
plotGrid = Table[Plot[Sin[x], x, 0, 2 Pi], 2, 2];
plotRowHeader =
Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], i, 2];
plotColumnHeader =
Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], i, 3,
4] // Prepend[Graphics[Style[Text["X"], 12]]];
graphicsGrid =
plotGrid // Prepend[plotRowHeader] // Transpose //
Prepend[plotColumnHeader];
GraphicsGrid[graphicsGrid]
answered 3 hours ago
Rohit NamjoshiRohit Namjoshi
1,4921213
answered 3 hours ago
Rohit NamjoshiRohit Namjoshi
1,4921213
answered 3 hours ago
Rohit NamjoshiRohit Namjoshi
1,4921213
answered 3 hours ago
Rohit NamjoshiRohit Namjoshi
1,4921213
1,4921213
add a comment |
add a comment |
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