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how to sum variables from file in bash


How to name a file in the deepest level of a directory treeUse & (ampersand) in single line bash loopScript with multiple arithmetic conditions failingbash division of numbers in text fileProblem with data comparison in if loopArithmetic syntax error with a number variablePrint file line-by-line, but handle the file changing mid-executionPutting string read from file inside double quotebash script to find files thinks the file name should be an integerString to integer in Shell






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















Hello I need to sum numbers from a file line by line.



The file:



1.0
0.46
0.67


I want to sum, then divide 3.



I currently have:



while IFS= read -r var
do
x=$(($var + $x)) | bc -l
done < "file.txt"
echo "$x / 3"


My error:



-bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")









share|improve this question






























    1















    Hello I need to sum numbers from a file line by line.



    The file:



    1.0
    0.46
    0.67


    I want to sum, then divide 3.



    I currently have:



    while IFS= read -r var
    do
    x=$(($var + $x)) | bc -l
    done < "file.txt"
    echo "$x / 3"


    My error:



    -bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")









    share|improve this question


























      1












      1








      1








      Hello I need to sum numbers from a file line by line.



      The file:



      1.0
      0.46
      0.67


      I want to sum, then divide 3.



      I currently have:



      while IFS= read -r var
      do
      x=$(($var + $x)) | bc -l
      done < "file.txt"
      echo "$x / 3"


      My error:



      -bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")









      share|improve this question
















      Hello I need to sum numbers from a file line by line.



      The file:



      1.0
      0.46
      0.67


      I want to sum, then divide 3.



      I currently have:



      while IFS= read -r var
      do
      x=$(($var + $x)) | bc -l
      done < "file.txt"
      echo "$x / 3"


      My error:



      -bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")






      bash arithmetic






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 2 hours ago









      Jesse_b

      14.7k33574




      14.7k33574










      asked 2 hours ago









      AhmetMelihBaşbuğAhmetMelihBaşbuğ

      1175




      1175




















          3 Answers
          3






          active

          oldest

          votes


















          3














          bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:



          awk 'sum= sum+$1 END print sum/3' file


          This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.






          share|improve this answer






























            1














            Just for fun



            $ paste -sd+ file | dc -e2k0 -f- -e+3/p
            .71





            share|improve this answer






























              0














              Try this:



              x=0
              while IFS= read -r var; do
              x="$(echo "$var + $x" | bc -l)"
              done < "file.txt"
              echo "$x / 3" | bc -l



              1. x was not defined.

              2. You need an echo for bc to work (not mixed bash arithmetic).





              share|improve this answer























                Your Answer








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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                3














                bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:



                awk 'sum= sum+$1 END print sum/3' file


                This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.






                share|improve this answer



























                  3














                  bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:



                  awk 'sum= sum+$1 END print sum/3' file


                  This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.






                  share|improve this answer

























                    3












                    3








                    3







                    bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:



                    awk 'sum= sum+$1 END print sum/3' file


                    This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.






                    share|improve this answer













                    bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:



                    awk 'sum= sum+$1 END print sum/3' file


                    This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 2 hours ago









                    Jesse_bJesse_b

                    14.7k33574




                    14.7k33574























                        1














                        Just for fun



                        $ paste -sd+ file | dc -e2k0 -f- -e+3/p
                        .71





                        share|improve this answer



























                          1














                          Just for fun



                          $ paste -sd+ file | dc -e2k0 -f- -e+3/p
                          .71





                          share|improve this answer

























                            1












                            1








                            1







                            Just for fun



                            $ paste -sd+ file | dc -e2k0 -f- -e+3/p
                            .71





                            share|improve this answer













                            Just for fun



                            $ paste -sd+ file | dc -e2k0 -f- -e+3/p
                            .71






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 1 hour ago









                            steeldriversteeldriver

                            38.2k45489




                            38.2k45489





















                                0














                                Try this:



                                x=0
                                while IFS= read -r var; do
                                x="$(echo "$var + $x" | bc -l)"
                                done < "file.txt"
                                echo "$x / 3" | bc -l



                                1. x was not defined.

                                2. You need an echo for bc to work (not mixed bash arithmetic).





                                share|improve this answer



























                                  0














                                  Try this:



                                  x=0
                                  while IFS= read -r var; do
                                  x="$(echo "$var + $x" | bc -l)"
                                  done < "file.txt"
                                  echo "$x / 3" | bc -l



                                  1. x was not defined.

                                  2. You need an echo for bc to work (not mixed bash arithmetic).





                                  share|improve this answer

























                                    0












                                    0








                                    0







                                    Try this:



                                    x=0
                                    while IFS= read -r var; do
                                    x="$(echo "$var + $x" | bc -l)"
                                    done < "file.txt"
                                    echo "$x / 3" | bc -l



                                    1. x was not defined.

                                    2. You need an echo for bc to work (not mixed bash arithmetic).





                                    share|improve this answer













                                    Try this:



                                    x=0
                                    while IFS= read -r var; do
                                    x="$(echo "$var + $x" | bc -l)"
                                    done < "file.txt"
                                    echo "$x / 3" | bc -l



                                    1. x was not defined.

                                    2. You need an echo for bc to work (not mixed bash arithmetic).






                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered 2 hours ago









                                    FreddyFreddy

                                    2,241210




                                    2,241210



























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