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How to fade a semiplane defined by line?
How can I stop defined points that are not displayed from influencing image size?LaTeX complains that tkzDrawArc is not definedHow to draw a dashed line and length with tkz-euclideColor fade a line in tikzpictureHow may I extend (prolong or produce) a line segment accurately in the following geometrical figure?Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingDraw Perpendicular to a lineHow to fade the color of an angle?Fade draw and fill in TikZHow to use points defined in tkz-euclide in tikz?
With the following code:
documentclass[tikz]standalone
usepackagetkz-euclide,tkz-fct,amsmath
usetkzobjall
begindocument
begintikzpicture[anchor=center]
tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
tkzDefPoints.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A
tkzDrawX[noticks, label=(operatornameRe(x) )]
tkzDrawY[noticks, label=(operatornameIm(x) )]
tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
tkzMarkRightAngle(A,M,P_1)
tkzFct[domain=-1:3, color=red, thick]x-.5
draw (P_1) -- (P_2);
tkzLabelPoints[above right](P_1,P_2)
tkzLabelPoints[right](M)
tkzText[color=black](1.5,3)(
endtikzpicture
enddocument
I'm getting:
I wanted to add a fade like this:
but I can't have the fade to be in the right angle.
How can I get this kind of fade, fadding to white?
tikz-pgf tkz-euclide
add a comment |
With the following code:
documentclass[tikz]standalone
usepackagetkz-euclide,tkz-fct,amsmath
usetkzobjall
begindocument
begintikzpicture[anchor=center]
tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
tkzDefPoints.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A
tkzDrawX[noticks, label=(operatornameRe(x) )]
tkzDrawY[noticks, label=(operatornameIm(x) )]
tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
tkzMarkRightAngle(A,M,P_1)
tkzFct[domain=-1:3, color=red, thick]x-.5
draw (P_1) -- (P_2);
tkzLabelPoints[above right](P_1,P_2)
tkzLabelPoints[right](M)
tkzText[color=black](1.5,3)(
endtikzpicture
enddocument
I'm getting:
I wanted to add a fade like this:
but I can't have the fade to be in the right angle.
How can I get this kind of fade, fadding to white?
tikz-pgf tkz-euclide
add a comment |
With the following code:
documentclass[tikz]standalone
usepackagetkz-euclide,tkz-fct,amsmath
usetkzobjall
begindocument
begintikzpicture[anchor=center]
tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
tkzDefPoints.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A
tkzDrawX[noticks, label=(operatornameRe(x) )]
tkzDrawY[noticks, label=(operatornameIm(x) )]
tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
tkzMarkRightAngle(A,M,P_1)
tkzFct[domain=-1:3, color=red, thick]x-.5
draw (P_1) -- (P_2);
tkzLabelPoints[above right](P_1,P_2)
tkzLabelPoints[right](M)
tkzText[color=black](1.5,3)(
endtikzpicture
enddocument
I'm getting:
I wanted to add a fade like this:
but I can't have the fade to be in the right angle.
How can I get this kind of fade, fadding to white?
tikz-pgf tkz-euclide
With the following code:
documentclass[tikz]standalone
usepackagetkz-euclide,tkz-fct,amsmath
usetkzobjall
begindocument
begintikzpicture[anchor=center]
tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
tkzDefPoints.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A
tkzDrawX[noticks, label=(operatornameRe(x) )]
tkzDrawY[noticks, label=(operatornameIm(x) )]
tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
tkzMarkRightAngle(A,M,P_1)
tkzFct[domain=-1:3, color=red, thick]x-.5
draw (P_1) -- (P_2);
tkzLabelPoints[above right](P_1,P_2)
tkzLabelPoints[right](M)
tkzText[color=black](1.5,3)(
endtikzpicture
enddocument
I'm getting:
I wanted to add a fade like this:
but I can't have the fade to be in the right angle.
How can I get this kind of fade, fadding to white?
tikz-pgf tkz-euclide
tikz-pgf tkz-euclide
asked 5 hours ago
Concept7Concept7
916
916
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'
documentclass[tikz,border=5mm]standalone
usepackagetkz-euclide
usetkzobjall
begindocument
begintikzpicture
coordinate[label=above right:$P_1$] (P1) at (.5,2);
coordinate[label=above right:$P_2$] (P2) at (2.5,0);
coordinate[label=right:$M$] (M) at (1.5,1);
coordinate (A) at (2,1.5);
pgfmathsetmacroa.5-sqrt(2)
pgfmathsetmacrob.5+sqrt(12.5)
shade[top color=white,bottom color=red!50,
transform canvas=rotate around=45:(.5,0)]
(a,0) rectangle (b,.5);
draw[-latex] (-1,0)--(3.5,0) node[below]rmRe$(x)$;
draw[-latex] (0,-1)--(0,3.5) node[left]rmIm$(x)$;
draw (P1) -- (P2);
draw[red,thick] plot[domain=-.5:3] (x,x-.5);
foreach p in P1,P2,M
fill (p) circle(1pt);
node at (1.5,3)(;
tkzMarkRightAngle(P1,M,A)
endtikzpicture
enddocument
add a comment |
This is in principle very simple but tkz-euclide
seems to mess up things a bit. One can just use a shading angle
, which can, of course, be computed by TikZ.
documentclass[tikz]standalone
usetikzlibrarycalc,backgrounds
usepackageamsmath
DeclareMathOperatorreRe
DeclareMathOperatorimIm
begindocument
begintikzpicture[anchor=center,declare function=f(x)=x-0.5;
xmin=-1;xmax=3;]
draw[-latex] (-1.5,0) -- (3.5,0) node[below left]$re z$;
draw[-latex] (0,-1.5) -- (0,3.5) node[below left]$im z$;;
path foreach X/Y/L/P in .5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0
(X,Y) coordinate[label=P:$L$] (L);
beginscope[on background layer]
shade let p1=(xmin,f(xmin)),p2=(xmax,f(xmax)),
n1=atan2(y2-y1,x2-x1) in
[left color=white,right color=red,middle color=white,shading angle=n1]
(p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
;
endscope
draw[red,thick] plot[variable=x,domain=xmin:xmax] (x,f(x));
draw (P_1) -- (P_2);
node[anchor=south,red] at (1.5,3) z-z_1;
endtikzpicture
enddocument
1
I like your answer, and the correction ofre(x)
andim(x)
:).
– manooooh
27 mins ago
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
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oldest
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active
oldest
votes
You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'
documentclass[tikz,border=5mm]standalone
usepackagetkz-euclide
usetkzobjall
begindocument
begintikzpicture
coordinate[label=above right:$P_1$] (P1) at (.5,2);
coordinate[label=above right:$P_2$] (P2) at (2.5,0);
coordinate[label=right:$M$] (M) at (1.5,1);
coordinate (A) at (2,1.5);
pgfmathsetmacroa.5-sqrt(2)
pgfmathsetmacrob.5+sqrt(12.5)
shade[top color=white,bottom color=red!50,
transform canvas=rotate around=45:(.5,0)]
(a,0) rectangle (b,.5);
draw[-latex] (-1,0)--(3.5,0) node[below]rmRe$(x)$;
draw[-latex] (0,-1)--(0,3.5) node[left]rmIm$(x)$;
draw (P1) -- (P2);
draw[red,thick] plot[domain=-.5:3] (x,x-.5);
foreach p in P1,P2,M
fill (p) circle(1pt);
node at (1.5,3)(;
tkzMarkRightAngle(P1,M,A)
endtikzpicture
enddocument
add a comment |
You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'
documentclass[tikz,border=5mm]standalone
usepackagetkz-euclide
usetkzobjall
begindocument
begintikzpicture
coordinate[label=above right:$P_1$] (P1) at (.5,2);
coordinate[label=above right:$P_2$] (P2) at (2.5,0);
coordinate[label=right:$M$] (M) at (1.5,1);
coordinate (A) at (2,1.5);
pgfmathsetmacroa.5-sqrt(2)
pgfmathsetmacrob.5+sqrt(12.5)
shade[top color=white,bottom color=red!50,
transform canvas=rotate around=45:(.5,0)]
(a,0) rectangle (b,.5);
draw[-latex] (-1,0)--(3.5,0) node[below]rmRe$(x)$;
draw[-latex] (0,-1)--(0,3.5) node[left]rmIm$(x)$;
draw (P1) -- (P2);
draw[red,thick] plot[domain=-.5:3] (x,x-.5);
foreach p in P1,P2,M
fill (p) circle(1pt);
node at (1.5,3)(;
tkzMarkRightAngle(P1,M,A)
endtikzpicture
enddocument
add a comment |
You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'
documentclass[tikz,border=5mm]standalone
usepackagetkz-euclide
usetkzobjall
begindocument
begintikzpicture
coordinate[label=above right:$P_1$] (P1) at (.5,2);
coordinate[label=above right:$P_2$] (P2) at (2.5,0);
coordinate[label=right:$M$] (M) at (1.5,1);
coordinate (A) at (2,1.5);
pgfmathsetmacroa.5-sqrt(2)
pgfmathsetmacrob.5+sqrt(12.5)
shade[top color=white,bottom color=red!50,
transform canvas=rotate around=45:(.5,0)]
(a,0) rectangle (b,.5);
draw[-latex] (-1,0)--(3.5,0) node[below]rmRe$(x)$;
draw[-latex] (0,-1)--(0,3.5) node[left]rmIm$(x)$;
draw (P1) -- (P2);
draw[red,thick] plot[domain=-.5:3] (x,x-.5);
foreach p in P1,P2,M
fill (p) circle(1pt);
node at (1.5,3)(;
tkzMarkRightAngle(P1,M,A)
endtikzpicture
enddocument
You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'
documentclass[tikz,border=5mm]standalone
usepackagetkz-euclide
usetkzobjall
begindocument
begintikzpicture
coordinate[label=above right:$P_1$] (P1) at (.5,2);
coordinate[label=above right:$P_2$] (P2) at (2.5,0);
coordinate[label=right:$M$] (M) at (1.5,1);
coordinate (A) at (2,1.5);
pgfmathsetmacroa.5-sqrt(2)
pgfmathsetmacrob.5+sqrt(12.5)
shade[top color=white,bottom color=red!50,
transform canvas=rotate around=45:(.5,0)]
(a,0) rectangle (b,.5);
draw[-latex] (-1,0)--(3.5,0) node[below]rmRe$(x)$;
draw[-latex] (0,-1)--(0,3.5) node[left]rmIm$(x)$;
draw (P1) -- (P2);
draw[red,thick] plot[domain=-.5:3] (x,x-.5);
foreach p in P1,P2,M
fill (p) circle(1pt);
node at (1.5,3)(;
tkzMarkRightAngle(P1,M,A)
endtikzpicture
enddocument
answered 5 hours ago
Black MildBlack Mild
697611
697611
add a comment |
add a comment |
This is in principle very simple but tkz-euclide
seems to mess up things a bit. One can just use a shading angle
, which can, of course, be computed by TikZ.
documentclass[tikz]standalone
usetikzlibrarycalc,backgrounds
usepackageamsmath
DeclareMathOperatorreRe
DeclareMathOperatorimIm
begindocument
begintikzpicture[anchor=center,declare function=f(x)=x-0.5;
xmin=-1;xmax=3;]
draw[-latex] (-1.5,0) -- (3.5,0) node[below left]$re z$;
draw[-latex] (0,-1.5) -- (0,3.5) node[below left]$im z$;;
path foreach X/Y/L/P in .5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0
(X,Y) coordinate[label=P:$L$] (L);
beginscope[on background layer]
shade let p1=(xmin,f(xmin)),p2=(xmax,f(xmax)),
n1=atan2(y2-y1,x2-x1) in
[left color=white,right color=red,middle color=white,shading angle=n1]
(p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
;
endscope
draw[red,thick] plot[variable=x,domain=xmin:xmax] (x,f(x));
draw (P_1) -- (P_2);
node[anchor=south,red] at (1.5,3) z-z_1;
endtikzpicture
enddocument
1
I like your answer, and the correction ofre(x)
andim(x)
:).
– manooooh
27 mins ago
add a comment |
This is in principle very simple but tkz-euclide
seems to mess up things a bit. One can just use a shading angle
, which can, of course, be computed by TikZ.
documentclass[tikz]standalone
usetikzlibrarycalc,backgrounds
usepackageamsmath
DeclareMathOperatorreRe
DeclareMathOperatorimIm
begindocument
begintikzpicture[anchor=center,declare function=f(x)=x-0.5;
xmin=-1;xmax=3;]
draw[-latex] (-1.5,0) -- (3.5,0) node[below left]$re z$;
draw[-latex] (0,-1.5) -- (0,3.5) node[below left]$im z$;;
path foreach X/Y/L/P in .5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0
(X,Y) coordinate[label=P:$L$] (L);
beginscope[on background layer]
shade let p1=(xmin,f(xmin)),p2=(xmax,f(xmax)),
n1=atan2(y2-y1,x2-x1) in
[left color=white,right color=red,middle color=white,shading angle=n1]
(p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
;
endscope
draw[red,thick] plot[variable=x,domain=xmin:xmax] (x,f(x));
draw (P_1) -- (P_2);
node[anchor=south,red] at (1.5,3) z-z_1;
endtikzpicture
enddocument
1
I like your answer, and the correction ofre(x)
andim(x)
:).
– manooooh
27 mins ago
add a comment |
This is in principle very simple but tkz-euclide
seems to mess up things a bit. One can just use a shading angle
, which can, of course, be computed by TikZ.
documentclass[tikz]standalone
usetikzlibrarycalc,backgrounds
usepackageamsmath
DeclareMathOperatorreRe
DeclareMathOperatorimIm
begindocument
begintikzpicture[anchor=center,declare function=f(x)=x-0.5;
xmin=-1;xmax=3;]
draw[-latex] (-1.5,0) -- (3.5,0) node[below left]$re z$;
draw[-latex] (0,-1.5) -- (0,3.5) node[below left]$im z$;;
path foreach X/Y/L/P in .5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0
(X,Y) coordinate[label=P:$L$] (L);
beginscope[on background layer]
shade let p1=(xmin,f(xmin)),p2=(xmax,f(xmax)),
n1=atan2(y2-y1,x2-x1) in
[left color=white,right color=red,middle color=white,shading angle=n1]
(p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
;
endscope
draw[red,thick] plot[variable=x,domain=xmin:xmax] (x,f(x));
draw (P_1) -- (P_2);
node[anchor=south,red] at (1.5,3) z-z_1;
endtikzpicture
enddocument
This is in principle very simple but tkz-euclide
seems to mess up things a bit. One can just use a shading angle
, which can, of course, be computed by TikZ.
documentclass[tikz]standalone
usetikzlibrarycalc,backgrounds
usepackageamsmath
DeclareMathOperatorreRe
DeclareMathOperatorimIm
begindocument
begintikzpicture[anchor=center,declare function=f(x)=x-0.5;
xmin=-1;xmax=3;]
draw[-latex] (-1.5,0) -- (3.5,0) node[below left]$re z$;
draw[-latex] (0,-1.5) -- (0,3.5) node[below left]$im z$;;
path foreach X/Y/L/P in .5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0
(X,Y) coordinate[label=P:$L$] (L);
beginscope[on background layer]
shade let p1=(xmin,f(xmin)),p2=(xmax,f(xmax)),
n1=atan2(y2-y1,x2-x1) in
[left color=white,right color=red,middle color=white,shading angle=n1]
(p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
;
endscope
draw[red,thick] plot[variable=x,domain=xmin:xmax] (x,f(x));
draw (P_1) -- (P_2);
node[anchor=south,red] at (1.5,3) z-z_1;
endtikzpicture
enddocument
edited 4 hours ago
answered 5 hours ago
marmotmarmot
111k5138257
111k5138257
1
I like your answer, and the correction ofre(x)
andim(x)
:).
– manooooh
27 mins ago
add a comment |
1
I like your answer, and the correction ofre(x)
andim(x)
:).
– manooooh
27 mins ago
1
1
I like your answer, and the correction of
re(x)
and im(x)
:).– manooooh
27 mins ago
I like your answer, and the correction of
re(x)
and im(x)
:).– manooooh
27 mins ago
add a comment |
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