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Integral Notations in Quantum Mechanics
Why is the $dx$ right next to the integral sign in QFT literature?Is there a recognised standard for typesetting quantum mechanical operators?What's the correct link between Dirac notation and wave mechanics integrals?Notation of integralsLine integral in cylindrical coordinates? Confused over notationWhat is the meaning of the double complex integral notation used in physics?flux-flux correlation function under Feynman's path integralBreaking up an Integral FurtherHow does spin enter into the path integral approach to quantum mechanics?Hermitian operator followed by another hermitian operator – is it also hermitian?Time evolution operator in QM
$begingroup$
I've been learning about Quantum Dynamics, time evolution operators, etc. I am confused about the notation used in integrals. Normally I am used to integrals written in this way (with $dx$ on the right side):
$$int f(x)dx$$
In this manner of notation, I can easily see the integrand as it is sandwiched by the integral sign and the $dx$.
However, I often see integrals written in this way (with $dx$ beside the integral sign):
$$int dx f(x)$$
Is this notation not ambiguous? This is especially confusing for me when used in products, as I cannot identify what is the integrand sometimes. For example, I don't understand which is true in the following (when evaluating time evolution operator): $$beginalignleft(int ^t_t_0 dt' H(t')right)^2stackrel?=int ^t_t_0 H(t') dt'int ^t_t_0 H(t'')dt''\stackrel?=int ^t_t_0 dt' H(t')int ^t_t_0 dt'' H(t'')\stackrel?=int ^t_t_0 dt'int ^t_t_0 dt'' H(t') H(t'') endalign$$
The last line is especially confusing for me as I'm not sure if the integrand changes. Could I please get clarification for these different notations? Is there a reason for such notation? (If I'm not wrong, it is to group the integrals and the integrands in separate places for convenience? I'm not sure if it sacrifices clarity for this though.)
EDIT: There is also an issue of when operators are involved:
$$beginalignint dx hatF(x) hatG(x)stackrel?=int hatF(x)dxhatG(x)\stackrel?=int hatF(x)hatG(x)dxendalign$$
How do you know which operator is in the integrand? And assuming the general case where $hatF$ and $hatG$ do not commute, you cannot write the integral with $hatG(x)$ on the left of the integral. How is this not ambiguous?
quantum-mechanics notation integration
$endgroup$
add a comment |
$begingroup$
I've been learning about Quantum Dynamics, time evolution operators, etc. I am confused about the notation used in integrals. Normally I am used to integrals written in this way (with $dx$ on the right side):
$$int f(x)dx$$
In this manner of notation, I can easily see the integrand as it is sandwiched by the integral sign and the $dx$.
However, I often see integrals written in this way (with $dx$ beside the integral sign):
$$int dx f(x)$$
Is this notation not ambiguous? This is especially confusing for me when used in products, as I cannot identify what is the integrand sometimes. For example, I don't understand which is true in the following (when evaluating time evolution operator): $$beginalignleft(int ^t_t_0 dt' H(t')right)^2stackrel?=int ^t_t_0 H(t') dt'int ^t_t_0 H(t'')dt''\stackrel?=int ^t_t_0 dt' H(t')int ^t_t_0 dt'' H(t'')\stackrel?=int ^t_t_0 dt'int ^t_t_0 dt'' H(t') H(t'') endalign$$
The last line is especially confusing for me as I'm not sure if the integrand changes. Could I please get clarification for these different notations? Is there a reason for such notation? (If I'm not wrong, it is to group the integrals and the integrands in separate places for convenience? I'm not sure if it sacrifices clarity for this though.)
EDIT: There is also an issue of when operators are involved:
$$beginalignint dx hatF(x) hatG(x)stackrel?=int hatF(x)dxhatG(x)\stackrel?=int hatF(x)hatG(x)dxendalign$$
How do you know which operator is in the integrand? And assuming the general case where $hatF$ and $hatG$ do not commute, you cannot write the integral with $hatG(x)$ on the left of the integral. How is this not ambiguous?
quantum-mechanics notation integration
$endgroup$
$begingroup$
Related: physics.stackexchange.com/q/200378/2451, math.stackexchange.com/q/387572/11127
$endgroup$
– Qmechanic♦
1 hour ago
add a comment |
$begingroup$
I've been learning about Quantum Dynamics, time evolution operators, etc. I am confused about the notation used in integrals. Normally I am used to integrals written in this way (with $dx$ on the right side):
$$int f(x)dx$$
In this manner of notation, I can easily see the integrand as it is sandwiched by the integral sign and the $dx$.
However, I often see integrals written in this way (with $dx$ beside the integral sign):
$$int dx f(x)$$
Is this notation not ambiguous? This is especially confusing for me when used in products, as I cannot identify what is the integrand sometimes. For example, I don't understand which is true in the following (when evaluating time evolution operator): $$beginalignleft(int ^t_t_0 dt' H(t')right)^2stackrel?=int ^t_t_0 H(t') dt'int ^t_t_0 H(t'')dt''\stackrel?=int ^t_t_0 dt' H(t')int ^t_t_0 dt'' H(t'')\stackrel?=int ^t_t_0 dt'int ^t_t_0 dt'' H(t') H(t'') endalign$$
The last line is especially confusing for me as I'm not sure if the integrand changes. Could I please get clarification for these different notations? Is there a reason for such notation? (If I'm not wrong, it is to group the integrals and the integrands in separate places for convenience? I'm not sure if it sacrifices clarity for this though.)
EDIT: There is also an issue of when operators are involved:
$$beginalignint dx hatF(x) hatG(x)stackrel?=int hatF(x)dxhatG(x)\stackrel?=int hatF(x)hatG(x)dxendalign$$
How do you know which operator is in the integrand? And assuming the general case where $hatF$ and $hatG$ do not commute, you cannot write the integral with $hatG(x)$ on the left of the integral. How is this not ambiguous?
quantum-mechanics notation integration
$endgroup$
I've been learning about Quantum Dynamics, time evolution operators, etc. I am confused about the notation used in integrals. Normally I am used to integrals written in this way (with $dx$ on the right side):
$$int f(x)dx$$
In this manner of notation, I can easily see the integrand as it is sandwiched by the integral sign and the $dx$.
However, I often see integrals written in this way (with $dx$ beside the integral sign):
$$int dx f(x)$$
Is this notation not ambiguous? This is especially confusing for me when used in products, as I cannot identify what is the integrand sometimes. For example, I don't understand which is true in the following (when evaluating time evolution operator): $$beginalignleft(int ^t_t_0 dt' H(t')right)^2stackrel?=int ^t_t_0 H(t') dt'int ^t_t_0 H(t'')dt''\stackrel?=int ^t_t_0 dt' H(t')int ^t_t_0 dt'' H(t'')\stackrel?=int ^t_t_0 dt'int ^t_t_0 dt'' H(t') H(t'') endalign$$
The last line is especially confusing for me as I'm not sure if the integrand changes. Could I please get clarification for these different notations? Is there a reason for such notation? (If I'm not wrong, it is to group the integrals and the integrands in separate places for convenience? I'm not sure if it sacrifices clarity for this though.)
EDIT: There is also an issue of when operators are involved:
$$beginalignint dx hatF(x) hatG(x)stackrel?=int hatF(x)dxhatG(x)\stackrel?=int hatF(x)hatG(x)dxendalign$$
How do you know which operator is in the integrand? And assuming the general case where $hatF$ and $hatG$ do not commute, you cannot write the integral with $hatG(x)$ on the left of the integral. How is this not ambiguous?
quantum-mechanics notation integration
quantum-mechanics notation integration
edited 1 hour ago
Hexiang Chang
asked 1 hour ago
Hexiang ChangHexiang Chang
100211
100211
$begingroup$
Related: physics.stackexchange.com/q/200378/2451, math.stackexchange.com/q/387572/11127
$endgroup$
– Qmechanic♦
1 hour ago
add a comment |
$begingroup$
Related: physics.stackexchange.com/q/200378/2451, math.stackexchange.com/q/387572/11127
$endgroup$
– Qmechanic♦
1 hour ago
$begingroup$
Related: physics.stackexchange.com/q/200378/2451, math.stackexchange.com/q/387572/11127
$endgroup$
– Qmechanic♦
1 hour ago
$begingroup$
Related: physics.stackexchange.com/q/200378/2451, math.stackexchange.com/q/387572/11127
$endgroup$
– Qmechanic♦
1 hour ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
I started seeing $$int dx f(x)$$ in my freshman year of undergraduate.
It's pretty common and the more you learn about integration the more it makes sense.
Now, regarding this part:
$$beginalignleft(int ^t_t_0 dt' H(t')right)^2stackrel?=int ^t_t_0 H(t') dt'int ^t_t_0 H(t'')dt''\stackrel?=int ^t_t_0 dt' H(t')int ^t_t_0 dt'' H(t'')\stackrel?=int ^t_t_0 dt'int ^t_t_0 dt'' H(t') H(t'') endalign$$
All of the equals signs there are correct.
Integrals factor like this:
$$
int dx int dy , f(x) , g(y) =
left( int dx , f(x) right) left( int dy ,g(y) right) , ,
$$
which is all you did there.
In fact, these are all the same:
beginalign
int int dx , dy , f(x) g(y)
&= int dx int dy , f(x) g(y) \
&= int dx , dy , f(x) g(y) \
&= left( int dx , f(x) right) left( int dy , g(y) right) \
&= left( int dx , f(x) right) left( int dx , g(x) right) \
endalign
Note, however, that you cannot factor something like this:
$$
int_0^t f(t') left( int_0^t' dt'' f(t'') right) dt'
$$
because the limit of the second integral depends on the first integral's integration variable.
You can, however, write it as
$$
int_0^t dt' f(t') int_0^t' dt'' f(t'') , .
$$
Operators
There is also an issue of when operators are involved:
$$beginalignint dx hatF(x) hatG(x)stackrel?=int hatF(x)dxhatG(x)\stackrel?=int hatF(x)hatG(x)dxendalign$$
There's really no difference.
The key is to remember that the $dx$ really doesn't mean anything other than to remind you which variable(s) in the integrand is being integrated.
By convention we tend to write the $dx$ either at the front or at the end.
I've never seen it written in the middle like that.
I think everyone would know what you mean, but putting the $dx$ is the middle of the integrands runs the risk that a reader won't notice them.
How do you know which operator is in the integrand?
Ok that's a good question!
It really comes down to the fact that notation has to be clear.
If you use the symbol $x$ to denote both an integration variable and a not-integrated variable, that's just asking for trouble.
It also shouldn't ever happen because integration variables are consumed by the integral, so they can't be referred to anywhere else in an equation.
For example, this makes no sense:
$$ g(x) = int_0^1 sin(x) dx$$
because there's no "free" $x$ on the right hand side.
And assuming the general case where $hatF$ and $hatG$ do not commute, you cannot write the integral with $hatG(x)$ on the left of the integral. How is this not ambiguous?
Well, you certainly would not write
$$ int dx hat F(x) hat G(x) neq left( int dx hat F(x) right) hat G(x) , .$$
That just makes no sense.
$endgroup$
$begingroup$
Thank you for a great answer! Could you please address my edit as well?
$endgroup$
– Hexiang Chang
1 hour ago
$begingroup$
I'm so sorry, I forgot that I needed to ask that as well
$endgroup$
– Hexiang Chang
1 hour ago
add a comment |
$begingroup$
The notation is not ambiguous; it's purely convention. The correspondence is
$$
left(
int_t_1^t_2 H(t) dt right) left( int_t'_1^t'_2H(t',t)dt' right)
iff int_t_1^t_2int_t'_1^t'_2H(t)H(t',t)dt' dt.
$$
That is instead of evaluating "inside out" we evaluate the integrals from right to left.
If you square an integral as
$$ left(int ^t_t_0 dt' H(t')right)^2 $$
you should know that in general these two integrals don't talk to one another, except in very special cases. That is, they are completely separate entities.
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add a comment |
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2 Answers
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2 Answers
2
active
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active
oldest
votes
$begingroup$
I started seeing $$int dx f(x)$$ in my freshman year of undergraduate.
It's pretty common and the more you learn about integration the more it makes sense.
Now, regarding this part:
$$beginalignleft(int ^t_t_0 dt' H(t')right)^2stackrel?=int ^t_t_0 H(t') dt'int ^t_t_0 H(t'')dt''\stackrel?=int ^t_t_0 dt' H(t')int ^t_t_0 dt'' H(t'')\stackrel?=int ^t_t_0 dt'int ^t_t_0 dt'' H(t') H(t'') endalign$$
All of the equals signs there are correct.
Integrals factor like this:
$$
int dx int dy , f(x) , g(y) =
left( int dx , f(x) right) left( int dy ,g(y) right) , ,
$$
which is all you did there.
In fact, these are all the same:
beginalign
int int dx , dy , f(x) g(y)
&= int dx int dy , f(x) g(y) \
&= int dx , dy , f(x) g(y) \
&= left( int dx , f(x) right) left( int dy , g(y) right) \
&= left( int dx , f(x) right) left( int dx , g(x) right) \
endalign
Note, however, that you cannot factor something like this:
$$
int_0^t f(t') left( int_0^t' dt'' f(t'') right) dt'
$$
because the limit of the second integral depends on the first integral's integration variable.
You can, however, write it as
$$
int_0^t dt' f(t') int_0^t' dt'' f(t'') , .
$$
Operators
There is also an issue of when operators are involved:
$$beginalignint dx hatF(x) hatG(x)stackrel?=int hatF(x)dxhatG(x)\stackrel?=int hatF(x)hatG(x)dxendalign$$
There's really no difference.
The key is to remember that the $dx$ really doesn't mean anything other than to remind you which variable(s) in the integrand is being integrated.
By convention we tend to write the $dx$ either at the front or at the end.
I've never seen it written in the middle like that.
I think everyone would know what you mean, but putting the $dx$ is the middle of the integrands runs the risk that a reader won't notice them.
How do you know which operator is in the integrand?
Ok that's a good question!
It really comes down to the fact that notation has to be clear.
If you use the symbol $x$ to denote both an integration variable and a not-integrated variable, that's just asking for trouble.
It also shouldn't ever happen because integration variables are consumed by the integral, so they can't be referred to anywhere else in an equation.
For example, this makes no sense:
$$ g(x) = int_0^1 sin(x) dx$$
because there's no "free" $x$ on the right hand side.
And assuming the general case where $hatF$ and $hatG$ do not commute, you cannot write the integral with $hatG(x)$ on the left of the integral. How is this not ambiguous?
Well, you certainly would not write
$$ int dx hat F(x) hat G(x) neq left( int dx hat F(x) right) hat G(x) , .$$
That just makes no sense.
$endgroup$
$begingroup$
Thank you for a great answer! Could you please address my edit as well?
$endgroup$
– Hexiang Chang
1 hour ago
$begingroup$
I'm so sorry, I forgot that I needed to ask that as well
$endgroup$
– Hexiang Chang
1 hour ago
add a comment |
$begingroup$
I started seeing $$int dx f(x)$$ in my freshman year of undergraduate.
It's pretty common and the more you learn about integration the more it makes sense.
Now, regarding this part:
$$beginalignleft(int ^t_t_0 dt' H(t')right)^2stackrel?=int ^t_t_0 H(t') dt'int ^t_t_0 H(t'')dt''\stackrel?=int ^t_t_0 dt' H(t')int ^t_t_0 dt'' H(t'')\stackrel?=int ^t_t_0 dt'int ^t_t_0 dt'' H(t') H(t'') endalign$$
All of the equals signs there are correct.
Integrals factor like this:
$$
int dx int dy , f(x) , g(y) =
left( int dx , f(x) right) left( int dy ,g(y) right) , ,
$$
which is all you did there.
In fact, these are all the same:
beginalign
int int dx , dy , f(x) g(y)
&= int dx int dy , f(x) g(y) \
&= int dx , dy , f(x) g(y) \
&= left( int dx , f(x) right) left( int dy , g(y) right) \
&= left( int dx , f(x) right) left( int dx , g(x) right) \
endalign
Note, however, that you cannot factor something like this:
$$
int_0^t f(t') left( int_0^t' dt'' f(t'') right) dt'
$$
because the limit of the second integral depends on the first integral's integration variable.
You can, however, write it as
$$
int_0^t dt' f(t') int_0^t' dt'' f(t'') , .
$$
Operators
There is also an issue of when operators are involved:
$$beginalignint dx hatF(x) hatG(x)stackrel?=int hatF(x)dxhatG(x)\stackrel?=int hatF(x)hatG(x)dxendalign$$
There's really no difference.
The key is to remember that the $dx$ really doesn't mean anything other than to remind you which variable(s) in the integrand is being integrated.
By convention we tend to write the $dx$ either at the front or at the end.
I've never seen it written in the middle like that.
I think everyone would know what you mean, but putting the $dx$ is the middle of the integrands runs the risk that a reader won't notice them.
How do you know which operator is in the integrand?
Ok that's a good question!
It really comes down to the fact that notation has to be clear.
If you use the symbol $x$ to denote both an integration variable and a not-integrated variable, that's just asking for trouble.
It also shouldn't ever happen because integration variables are consumed by the integral, so they can't be referred to anywhere else in an equation.
For example, this makes no sense:
$$ g(x) = int_0^1 sin(x) dx$$
because there's no "free" $x$ on the right hand side.
And assuming the general case where $hatF$ and $hatG$ do not commute, you cannot write the integral with $hatG(x)$ on the left of the integral. How is this not ambiguous?
Well, you certainly would not write
$$ int dx hat F(x) hat G(x) neq left( int dx hat F(x) right) hat G(x) , .$$
That just makes no sense.
$endgroup$
$begingroup$
Thank you for a great answer! Could you please address my edit as well?
$endgroup$
– Hexiang Chang
1 hour ago
$begingroup$
I'm so sorry, I forgot that I needed to ask that as well
$endgroup$
– Hexiang Chang
1 hour ago
add a comment |
$begingroup$
I started seeing $$int dx f(x)$$ in my freshman year of undergraduate.
It's pretty common and the more you learn about integration the more it makes sense.
Now, regarding this part:
$$beginalignleft(int ^t_t_0 dt' H(t')right)^2stackrel?=int ^t_t_0 H(t') dt'int ^t_t_0 H(t'')dt''\stackrel?=int ^t_t_0 dt' H(t')int ^t_t_0 dt'' H(t'')\stackrel?=int ^t_t_0 dt'int ^t_t_0 dt'' H(t') H(t'') endalign$$
All of the equals signs there are correct.
Integrals factor like this:
$$
int dx int dy , f(x) , g(y) =
left( int dx , f(x) right) left( int dy ,g(y) right) , ,
$$
which is all you did there.
In fact, these are all the same:
beginalign
int int dx , dy , f(x) g(y)
&= int dx int dy , f(x) g(y) \
&= int dx , dy , f(x) g(y) \
&= left( int dx , f(x) right) left( int dy , g(y) right) \
&= left( int dx , f(x) right) left( int dx , g(x) right) \
endalign
Note, however, that you cannot factor something like this:
$$
int_0^t f(t') left( int_0^t' dt'' f(t'') right) dt'
$$
because the limit of the second integral depends on the first integral's integration variable.
You can, however, write it as
$$
int_0^t dt' f(t') int_0^t' dt'' f(t'') , .
$$
Operators
There is also an issue of when operators are involved:
$$beginalignint dx hatF(x) hatG(x)stackrel?=int hatF(x)dxhatG(x)\stackrel?=int hatF(x)hatG(x)dxendalign$$
There's really no difference.
The key is to remember that the $dx$ really doesn't mean anything other than to remind you which variable(s) in the integrand is being integrated.
By convention we tend to write the $dx$ either at the front or at the end.
I've never seen it written in the middle like that.
I think everyone would know what you mean, but putting the $dx$ is the middle of the integrands runs the risk that a reader won't notice them.
How do you know which operator is in the integrand?
Ok that's a good question!
It really comes down to the fact that notation has to be clear.
If you use the symbol $x$ to denote both an integration variable and a not-integrated variable, that's just asking for trouble.
It also shouldn't ever happen because integration variables are consumed by the integral, so they can't be referred to anywhere else in an equation.
For example, this makes no sense:
$$ g(x) = int_0^1 sin(x) dx$$
because there's no "free" $x$ on the right hand side.
And assuming the general case where $hatF$ and $hatG$ do not commute, you cannot write the integral with $hatG(x)$ on the left of the integral. How is this not ambiguous?
Well, you certainly would not write
$$ int dx hat F(x) hat G(x) neq left( int dx hat F(x) right) hat G(x) , .$$
That just makes no sense.
$endgroup$
I started seeing $$int dx f(x)$$ in my freshman year of undergraduate.
It's pretty common and the more you learn about integration the more it makes sense.
Now, regarding this part:
$$beginalignleft(int ^t_t_0 dt' H(t')right)^2stackrel?=int ^t_t_0 H(t') dt'int ^t_t_0 H(t'')dt''\stackrel?=int ^t_t_0 dt' H(t')int ^t_t_0 dt'' H(t'')\stackrel?=int ^t_t_0 dt'int ^t_t_0 dt'' H(t') H(t'') endalign$$
All of the equals signs there are correct.
Integrals factor like this:
$$
int dx int dy , f(x) , g(y) =
left( int dx , f(x) right) left( int dy ,g(y) right) , ,
$$
which is all you did there.
In fact, these are all the same:
beginalign
int int dx , dy , f(x) g(y)
&= int dx int dy , f(x) g(y) \
&= int dx , dy , f(x) g(y) \
&= left( int dx , f(x) right) left( int dy , g(y) right) \
&= left( int dx , f(x) right) left( int dx , g(x) right) \
endalign
Note, however, that you cannot factor something like this:
$$
int_0^t f(t') left( int_0^t' dt'' f(t'') right) dt'
$$
because the limit of the second integral depends on the first integral's integration variable.
You can, however, write it as
$$
int_0^t dt' f(t') int_0^t' dt'' f(t'') , .
$$
Operators
There is also an issue of when operators are involved:
$$beginalignint dx hatF(x) hatG(x)stackrel?=int hatF(x)dxhatG(x)\stackrel?=int hatF(x)hatG(x)dxendalign$$
There's really no difference.
The key is to remember that the $dx$ really doesn't mean anything other than to remind you which variable(s) in the integrand is being integrated.
By convention we tend to write the $dx$ either at the front or at the end.
I've never seen it written in the middle like that.
I think everyone would know what you mean, but putting the $dx$ is the middle of the integrands runs the risk that a reader won't notice them.
How do you know which operator is in the integrand?
Ok that's a good question!
It really comes down to the fact that notation has to be clear.
If you use the symbol $x$ to denote both an integration variable and a not-integrated variable, that's just asking for trouble.
It also shouldn't ever happen because integration variables are consumed by the integral, so they can't be referred to anywhere else in an equation.
For example, this makes no sense:
$$ g(x) = int_0^1 sin(x) dx$$
because there's no "free" $x$ on the right hand side.
And assuming the general case where $hatF$ and $hatG$ do not commute, you cannot write the integral with $hatG(x)$ on the left of the integral. How is this not ambiguous?
Well, you certainly would not write
$$ int dx hat F(x) hat G(x) neq left( int dx hat F(x) right) hat G(x) , .$$
That just makes no sense.
edited 1 hour ago
answered 1 hour ago
DanielSankDanielSank
17.6k45178
17.6k45178
$begingroup$
Thank you for a great answer! Could you please address my edit as well?
$endgroup$
– Hexiang Chang
1 hour ago
$begingroup$
I'm so sorry, I forgot that I needed to ask that as well
$endgroup$
– Hexiang Chang
1 hour ago
add a comment |
$begingroup$
Thank you for a great answer! Could you please address my edit as well?
$endgroup$
– Hexiang Chang
1 hour ago
$begingroup$
I'm so sorry, I forgot that I needed to ask that as well
$endgroup$
– Hexiang Chang
1 hour ago
$begingroup$
Thank you for a great answer! Could you please address my edit as well?
$endgroup$
– Hexiang Chang
1 hour ago
$begingroup$
Thank you for a great answer! Could you please address my edit as well?
$endgroup$
– Hexiang Chang
1 hour ago
$begingroup$
I'm so sorry, I forgot that I needed to ask that as well
$endgroup$
– Hexiang Chang
1 hour ago
$begingroup$
I'm so sorry, I forgot that I needed to ask that as well
$endgroup$
– Hexiang Chang
1 hour ago
add a comment |
$begingroup$
The notation is not ambiguous; it's purely convention. The correspondence is
$$
left(
int_t_1^t_2 H(t) dt right) left( int_t'_1^t'_2H(t',t)dt' right)
iff int_t_1^t_2int_t'_1^t'_2H(t)H(t',t)dt' dt.
$$
That is instead of evaluating "inside out" we evaluate the integrals from right to left.
If you square an integral as
$$ left(int ^t_t_0 dt' H(t')right)^2 $$
you should know that in general these two integrals don't talk to one another, except in very special cases. That is, they are completely separate entities.
$endgroup$
add a comment |
$begingroup$
The notation is not ambiguous; it's purely convention. The correspondence is
$$
left(
int_t_1^t_2 H(t) dt right) left( int_t'_1^t'_2H(t',t)dt' right)
iff int_t_1^t_2int_t'_1^t'_2H(t)H(t',t)dt' dt.
$$
That is instead of evaluating "inside out" we evaluate the integrals from right to left.
If you square an integral as
$$ left(int ^t_t_0 dt' H(t')right)^2 $$
you should know that in general these two integrals don't talk to one another, except in very special cases. That is, they are completely separate entities.
$endgroup$
add a comment |
$begingroup$
The notation is not ambiguous; it's purely convention. The correspondence is
$$
left(
int_t_1^t_2 H(t) dt right) left( int_t'_1^t'_2H(t',t)dt' right)
iff int_t_1^t_2int_t'_1^t'_2H(t)H(t',t)dt' dt.
$$
That is instead of evaluating "inside out" we evaluate the integrals from right to left.
If you square an integral as
$$ left(int ^t_t_0 dt' H(t')right)^2 $$
you should know that in general these two integrals don't talk to one another, except in very special cases. That is, they are completely separate entities.
$endgroup$
The notation is not ambiguous; it's purely convention. The correspondence is
$$
left(
int_t_1^t_2 H(t) dt right) left( int_t'_1^t'_2H(t',t)dt' right)
iff int_t_1^t_2int_t'_1^t'_2H(t)H(t',t)dt' dt.
$$
That is instead of evaluating "inside out" we evaluate the integrals from right to left.
If you square an integral as
$$ left(int ^t_t_0 dt' H(t')right)^2 $$
you should know that in general these two integrals don't talk to one another, except in very special cases. That is, they are completely separate entities.
edited 1 hour ago
answered 1 hour ago
InertialObserverInertialObserver
3,2181027
3,2181027
add a comment |
add a comment |
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Related: physics.stackexchange.com/q/200378/2451, math.stackexchange.com/q/387572/11127
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