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How do I avoid eval and parse?
The Next CEO of Stack OverflowAvoiding the infamous “eval(parse())” constructR: eval(parse(…)) is often suboptimalWhy is using the JavaScript eval function a bad idea?When is JavaScript's eval() not evil?How to sort a dataframe by multiple column(s)?How to join (merge) data frames (inner, outer, left, right)What's the difference between eval, exec, and compile?How to make a great R reproducible exampleWhat does Python's eval() do? Avoiding the infamous “eval(parse())” constructUse argument value as variable name in R during function runR: eval parse function call not accessing correct environments
I have written a function that sources files that contain scripts for other functions and stores these functions in an alternative environment so that they aren't cluttering up the global environment. The code works, but contains two instances of eval(parse(...))
:
# sourceFunctionHidden ---------------------------
# source a function and hide the function from the global environment
sourceFunctionHidden <- function(functions, environment = "env", ...)
if (environment %in% search())
while (environment %in% search())
if (!exists("counter", inherits = F)) counter <- 0
eval(parse(text = paste0("detach(", environment, ")")))
counter <- counter + 1
cat("detached", counter, environment, "sn")
else cat("no", environment, "attachedn")
if (!environment %in% ls(.GlobalEnv, all.names = T))
assign(environment, new.env(), pos = .GlobalEnv)
cat("created", environment, "n")
else cat(environment, "already existsn")
sapply(functions, function(func)
# source(paste0("C:/Users/JT/R/Functions/", func, ".R"), .env)
source(paste0("C:/Users/JT/R/Functions/", func, ".R"))
eval(parse(text = paste0(environment, "$", func," <- ", func)))
cat(func, "created in", environment, "n")
)
# rm(list = functions, pos = .GlobalEnv)
eval(parse(text = paste0("attach(", environment, ")")))
cat("attached", environment, "nn")
Much has been written about the sub-optimality of the eval(parse(...))
construction (see here and here). However, the discussions that I've found mostly deal with alternate strategies for subsetting. The first instance of eval(parse(...))
in my code doesn't involve subsetting (the second instance might be related to subsetting).
Is there a way to call new.env(...)
and [environment name]$[function name] <- [function name]
without resorting to eval(parse(...))
? Thanks.
N.B.: I don't want to change the names of my functions to .name
to hide them in the global environment
r eval
add a comment |
I have written a function that sources files that contain scripts for other functions and stores these functions in an alternative environment so that they aren't cluttering up the global environment. The code works, but contains two instances of eval(parse(...))
:
# sourceFunctionHidden ---------------------------
# source a function and hide the function from the global environment
sourceFunctionHidden <- function(functions, environment = "env", ...)
if (environment %in% search())
while (environment %in% search())
if (!exists("counter", inherits = F)) counter <- 0
eval(parse(text = paste0("detach(", environment, ")")))
counter <- counter + 1
cat("detached", counter, environment, "sn")
else cat("no", environment, "attachedn")
if (!environment %in% ls(.GlobalEnv, all.names = T))
assign(environment, new.env(), pos = .GlobalEnv)
cat("created", environment, "n")
else cat(environment, "already existsn")
sapply(functions, function(func)
# source(paste0("C:/Users/JT/R/Functions/", func, ".R"), .env)
source(paste0("C:/Users/JT/R/Functions/", func, ".R"))
eval(parse(text = paste0(environment, "$", func," <- ", func)))
cat(func, "created in", environment, "n")
)
# rm(list = functions, pos = .GlobalEnv)
eval(parse(text = paste0("attach(", environment, ")")))
cat("attached", environment, "nn")
Much has been written about the sub-optimality of the eval(parse(...))
construction (see here and here). However, the discussions that I've found mostly deal with alternate strategies for subsetting. The first instance of eval(parse(...))
in my code doesn't involve subsetting (the second instance might be related to subsetting).
Is there a way to call new.env(...)
and [environment name]$[function name] <- [function name]
without resorting to eval(parse(...))
? Thanks.
N.B.: I don't want to change the names of my functions to .name
to hide them in the global environment
r eval
Just discovered thateval(parse(text = paste0("detach(", environment, ")")))
can be replaced withdetach(environment, character.only = T)
. The question about improvingeval(parse(text = paste0("attach(", environment, ")")))
remains.
– Josh
16 mins ago
add a comment |
I have written a function that sources files that contain scripts for other functions and stores these functions in an alternative environment so that they aren't cluttering up the global environment. The code works, but contains two instances of eval(parse(...))
:
# sourceFunctionHidden ---------------------------
# source a function and hide the function from the global environment
sourceFunctionHidden <- function(functions, environment = "env", ...)
if (environment %in% search())
while (environment %in% search())
if (!exists("counter", inherits = F)) counter <- 0
eval(parse(text = paste0("detach(", environment, ")")))
counter <- counter + 1
cat("detached", counter, environment, "sn")
else cat("no", environment, "attachedn")
if (!environment %in% ls(.GlobalEnv, all.names = T))
assign(environment, new.env(), pos = .GlobalEnv)
cat("created", environment, "n")
else cat(environment, "already existsn")
sapply(functions, function(func)
# source(paste0("C:/Users/JT/R/Functions/", func, ".R"), .env)
source(paste0("C:/Users/JT/R/Functions/", func, ".R"))
eval(parse(text = paste0(environment, "$", func," <- ", func)))
cat(func, "created in", environment, "n")
)
# rm(list = functions, pos = .GlobalEnv)
eval(parse(text = paste0("attach(", environment, ")")))
cat("attached", environment, "nn")
Much has been written about the sub-optimality of the eval(parse(...))
construction (see here and here). However, the discussions that I've found mostly deal with alternate strategies for subsetting. The first instance of eval(parse(...))
in my code doesn't involve subsetting (the second instance might be related to subsetting).
Is there a way to call new.env(...)
and [environment name]$[function name] <- [function name]
without resorting to eval(parse(...))
? Thanks.
N.B.: I don't want to change the names of my functions to .name
to hide them in the global environment
r eval
I have written a function that sources files that contain scripts for other functions and stores these functions in an alternative environment so that they aren't cluttering up the global environment. The code works, but contains two instances of eval(parse(...))
:
# sourceFunctionHidden ---------------------------
# source a function and hide the function from the global environment
sourceFunctionHidden <- function(functions, environment = "env", ...)
if (environment %in% search())
while (environment %in% search())
if (!exists("counter", inherits = F)) counter <- 0
eval(parse(text = paste0("detach(", environment, ")")))
counter <- counter + 1
cat("detached", counter, environment, "sn")
else cat("no", environment, "attachedn")
if (!environment %in% ls(.GlobalEnv, all.names = T))
assign(environment, new.env(), pos = .GlobalEnv)
cat("created", environment, "n")
else cat(environment, "already existsn")
sapply(functions, function(func)
# source(paste0("C:/Users/JT/R/Functions/", func, ".R"), .env)
source(paste0("C:/Users/JT/R/Functions/", func, ".R"))
eval(parse(text = paste0(environment, "$", func," <- ", func)))
cat(func, "created in", environment, "n")
)
# rm(list = functions, pos = .GlobalEnv)
eval(parse(text = paste0("attach(", environment, ")")))
cat("attached", environment, "nn")
Much has been written about the sub-optimality of the eval(parse(...))
construction (see here and here). However, the discussions that I've found mostly deal with alternate strategies for subsetting. The first instance of eval(parse(...))
in my code doesn't involve subsetting (the second instance might be related to subsetting).
Is there a way to call new.env(...)
and [environment name]$[function name] <- [function name]
without resorting to eval(parse(...))
? Thanks.
N.B.: I don't want to change the names of my functions to .name
to hide them in the global environment
r eval
r eval
asked 4 hours ago
JoshJosh
19512
19512
Just discovered thateval(parse(text = paste0("detach(", environment, ")")))
can be replaced withdetach(environment, character.only = T)
. The question about improvingeval(parse(text = paste0("attach(", environment, ")")))
remains.
– Josh
16 mins ago
add a comment |
Just discovered thateval(parse(text = paste0("detach(", environment, ")")))
can be replaced withdetach(environment, character.only = T)
. The question about improvingeval(parse(text = paste0("attach(", environment, ")")))
remains.
– Josh
16 mins ago
Just discovered that
eval(parse(text = paste0("detach(", environment, ")")))
can be replaced with detach(environment, character.only = T)
. The question about improving eval(parse(text = paste0("attach(", environment, ")")))
remains.– Josh
16 mins ago
Just discovered that
eval(parse(text = paste0("detach(", environment, ")")))
can be replaced with detach(environment, character.only = T)
. The question about improving eval(parse(text = paste0("attach(", environment, ")")))
remains.– Josh
16 mins ago
add a comment |
2 Answers
2
active
oldest
votes
If you want to keep it off global_env, put it into a package. It's common for people in the R community to put a bunch of frequently used helper functions into their own personal package.
I agree. I eventually need to learn how to do this.
– Josh
15 mins ago
add a comment |
For what its worth, the function source
actually uses eval(parse(...))
, albeit in a somewhat subtle way. First, .Internal(parse(...))
is used to create expressions, which after more processing are later passed to eval
. So eval(parse(...))
seems to be good enough for the R core team in this instance.
That said, you don't need to jump through hoops to source functions into a new environment. source
provides an argument local
that can be used for precisely this.
local: TRUE, FALSE or an environment, determining where the parsed expressions are evaluated.
An example:
env = new.env()
source('test.r', local = env)
testing it works:
env$test('hello', 'world')
# [1] "hello world"
ls(pattern = 'test')
# character(0)
And an example test.r
file to use this on:
test = function(a,b) paste(a,b)
Thank you, I missed that aspect ofsource()
. However, if I change that line of code tosource(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment)
I get the errorError in source(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment) : 'local' must be TRUE, FALSE or an environment
. Is there a way to convert the"env"
that comes fromenvironment
toenv
?
– Josh
7 mins ago
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you want to keep it off global_env, put it into a package. It's common for people in the R community to put a bunch of frequently used helper functions into their own personal package.
I agree. I eventually need to learn how to do this.
– Josh
15 mins ago
add a comment |
If you want to keep it off global_env, put it into a package. It's common for people in the R community to put a bunch of frequently used helper functions into their own personal package.
I agree. I eventually need to learn how to do this.
– Josh
15 mins ago
add a comment |
If you want to keep it off global_env, put it into a package. It's common for people in the R community to put a bunch of frequently used helper functions into their own personal package.
If you want to keep it off global_env, put it into a package. It's common for people in the R community to put a bunch of frequently used helper functions into their own personal package.
answered 3 hours ago
thcthc
5,37611224
5,37611224
I agree. I eventually need to learn how to do this.
– Josh
15 mins ago
add a comment |
I agree. I eventually need to learn how to do this.
– Josh
15 mins ago
I agree. I eventually need to learn how to do this.
– Josh
15 mins ago
I agree. I eventually need to learn how to do this.
– Josh
15 mins ago
add a comment |
For what its worth, the function source
actually uses eval(parse(...))
, albeit in a somewhat subtle way. First, .Internal(parse(...))
is used to create expressions, which after more processing are later passed to eval
. So eval(parse(...))
seems to be good enough for the R core team in this instance.
That said, you don't need to jump through hoops to source functions into a new environment. source
provides an argument local
that can be used for precisely this.
local: TRUE, FALSE or an environment, determining where the parsed expressions are evaluated.
An example:
env = new.env()
source('test.r', local = env)
testing it works:
env$test('hello', 'world')
# [1] "hello world"
ls(pattern = 'test')
# character(0)
And an example test.r
file to use this on:
test = function(a,b) paste(a,b)
Thank you, I missed that aspect ofsource()
. However, if I change that line of code tosource(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment)
I get the errorError in source(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment) : 'local' must be TRUE, FALSE or an environment
. Is there a way to convert the"env"
that comes fromenvironment
toenv
?
– Josh
7 mins ago
add a comment |
For what its worth, the function source
actually uses eval(parse(...))
, albeit in a somewhat subtle way. First, .Internal(parse(...))
is used to create expressions, which after more processing are later passed to eval
. So eval(parse(...))
seems to be good enough for the R core team in this instance.
That said, you don't need to jump through hoops to source functions into a new environment. source
provides an argument local
that can be used for precisely this.
local: TRUE, FALSE or an environment, determining where the parsed expressions are evaluated.
An example:
env = new.env()
source('test.r', local = env)
testing it works:
env$test('hello', 'world')
# [1] "hello world"
ls(pattern = 'test')
# character(0)
And an example test.r
file to use this on:
test = function(a,b) paste(a,b)
Thank you, I missed that aspect ofsource()
. However, if I change that line of code tosource(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment)
I get the errorError in source(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment) : 'local' must be TRUE, FALSE or an environment
. Is there a way to convert the"env"
that comes fromenvironment
toenv
?
– Josh
7 mins ago
add a comment |
For what its worth, the function source
actually uses eval(parse(...))
, albeit in a somewhat subtle way. First, .Internal(parse(...))
is used to create expressions, which after more processing are later passed to eval
. So eval(parse(...))
seems to be good enough for the R core team in this instance.
That said, you don't need to jump through hoops to source functions into a new environment. source
provides an argument local
that can be used for precisely this.
local: TRUE, FALSE or an environment, determining where the parsed expressions are evaluated.
An example:
env = new.env()
source('test.r', local = env)
testing it works:
env$test('hello', 'world')
# [1] "hello world"
ls(pattern = 'test')
# character(0)
And an example test.r
file to use this on:
test = function(a,b) paste(a,b)
For what its worth, the function source
actually uses eval(parse(...))
, albeit in a somewhat subtle way. First, .Internal(parse(...))
is used to create expressions, which after more processing are later passed to eval
. So eval(parse(...))
seems to be good enough for the R core team in this instance.
That said, you don't need to jump through hoops to source functions into a new environment. source
provides an argument local
that can be used for precisely this.
local: TRUE, FALSE or an environment, determining where the parsed expressions are evaluated.
An example:
env = new.env()
source('test.r', local = env)
testing it works:
env$test('hello', 'world')
# [1] "hello world"
ls(pattern = 'test')
# character(0)
And an example test.r
file to use this on:
test = function(a,b) paste(a,b)
answered 2 hours ago
dwwdww
15.9k32659
15.9k32659
Thank you, I missed that aspect ofsource()
. However, if I change that line of code tosource(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment)
I get the errorError in source(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment) : 'local' must be TRUE, FALSE or an environment
. Is there a way to convert the"env"
that comes fromenvironment
toenv
?
– Josh
7 mins ago
add a comment |
Thank you, I missed that aspect ofsource()
. However, if I change that line of code tosource(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment)
I get the errorError in source(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment) : 'local' must be TRUE, FALSE or an environment
. Is there a way to convert the"env"
that comes fromenvironment
toenv
?
– Josh
7 mins ago
Thank you, I missed that aspect of
source()
. However, if I change that line of code to source(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment)
I get the error Error in source(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment) : 'local' must be TRUE, FALSE or an environment
. Is there a way to convert the "env"
that comes from environment
to env
?– Josh
7 mins ago
Thank you, I missed that aspect of
source()
. However, if I change that line of code to source(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment)
I get the error Error in source(paste0("C:/Users/JT/R/Functions/", func, ".R"), local = environment) : 'local' must be TRUE, FALSE or an environment
. Is there a way to convert the "env"
that comes from environment
to env
?– Josh
7 mins ago
add a comment |
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Just discovered that
eval(parse(text = paste0("detach(", environment, ")")))
can be replaced withdetach(environment, character.only = T)
. The question about improvingeval(parse(text = paste0("attach(", environment, ")")))
remains.– Josh
16 mins ago