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Why would a new[] expression ever invoke a destructor?


About constructors/destructors and new/delete operators in C++ for custom objectsDoes delete call the destructor?Overloading operator delete in a base classWhen is %destructor invoked in BISON?Why should C++ programmers minimize use of 'new'?Why is ::operator new[] necessary when ::operator new is enough?Why am I permitted to declare an object with a deleted destructor?Does delete[] deallocate memory in one shot after invoking destructors?Why are non-placement `new` and `delete` built into the language and not just regular functions?Why deallocation function is not called when object constructor throw in a new expression?













8















From the C++17 standard (draft here), [expr.new]:




If the new-expression creates an object or an array of objects of class type, access and ambiguity control are done for the allocation function, the deallocation function, and the constructor. If the new-expression creates an array of objects of class type, the destructor is potentially invoked.




Why would new[] invoke a destructor? It's new, after all. It isn't delete.






c++ c++17 new-operator







share|improve this question




























    8















    From the C++17 standard (draft here), [expr.new]:




    If the new-expression creates an object or an array of objects of class type, access and ambiguity control are done for the allocation function, the deallocation function, and the constructor. If the new-expression creates an array of objects of class type, the destructor is potentially invoked.




    Why would new[] invoke a destructor? It's new, after all. It isn't delete.






    c++ c++17 new-operator







    share|improve this question


























      8












      8








      8








      From the C++17 standard (draft here), [expr.new]:




      If the new-expression creates an object or an array of objects of class type, access and ambiguity control are done for the allocation function, the deallocation function, and the constructor. If the new-expression creates an array of objects of class type, the destructor is potentially invoked.




      Why would new[] invoke a destructor? It's new, after all. It isn't delete.






      c++ c++17 new-operator







      share|improve this question
















      From the C++17 standard (draft here), [expr.new]:




      If the new-expression creates an object or an array of objects of class type, access and ambiguity control are done for the allocation function, the deallocation function, and the constructor. If the new-expression creates an array of objects of class type, the destructor is potentially invoked.




      Why would new[] invoke a destructor? It's new, after all. It isn't delete.






      c++ c++17 new-operator




      c++ c++17 new-operator






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 1 hour ago









      Cody Gray♦

      195k35382470




      195k35382470










      asked 2 hours ago









      thbthb

      8,66932355




      8,66932355






















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          If construction of any object in the buffer throws an exception, the previously constructed objects must be destructed. That requires an available destructor.






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            If construction of any object in the buffer throws an exception, the previously constructed objects must be destructed. That requires an available destructor.






            share|improve this answer





























              14














              If construction of any object in the buffer throws an exception, the previously constructed objects must be destructed. That requires an available destructor.






              share|improve this answer



























                14












                14








                14







                If construction of any object in the buffer throws an exception, the previously constructed objects must be destructed. That requires an available destructor.






                share|improve this answer















                If construction of any object in the buffer throws an exception, the previously constructed objects must be destructed. That requires an available destructor.







                share|improve this answer














                share|improve this answer



                share|improve this answer








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                Sombrero Chicken

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                answered 1 hour ago









                StoryTellerStoryTeller

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